Scala - 两个列表到元组列表
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Scala - Two Lists to Tuple List
提问by GJK
Last year I had quite a bit of experience with standard ML, but I haven't done any real functional programming in about 10 months. Now that I'm on the Scala bandwagon, I'm having trouble finding an operation which I used extensively in standard ML when writing a compiler (although to be fair, this method may not have been a library method).
去年我在标准 ML 方面有相当多的经验，但我已经有大约 10 个月没有做过任何真正的函数式编程了。现在我已经加入了 Scala 的潮流，我在编写编译器时很难找到我在标准 ML 中广泛使用的操作（尽管公平地说，这个方法可能不是一个库方法）。
Basically, I have two lists:
基本上，我有两个列表：
List("a","b","c")
List(1,2,3)
And I want an operation that will give me a list of tuples like this:
我想要一个操作，它会给我一个像这样的元组列表：
List(("a",1), ("b",2), ("c",3))
Is there a standard Scala function I can use to get this result? (I think we called it a zip function in standard ML, but that seems to refer to something different when I was searching for Scala zip functions.)
我可以使用标准的 Scala 函数来获得这个结果吗？（我认为我们在标准 ML 中将其称为 zip 函数，但是当我搜索 Scala zip 函数时，这似乎指的是不同的东西。）
回答by om-nom-nom
You're right you can use zip:
你是对的，你可以使用 zip：
val a = List("a","b","c")
// a: List[String] = List(a, b, c)
val b = List(1,2,3)
// b: List[Int] = List(1, 2, 3)
a zip b // beautified a.zip(b)
//res0: List[(String, Int)] = List((a,1), (b,2), (c,3))
