按月分组的 SQL 结果
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SQL Results group by month
提问by madlan
I'm trying to return some results spread over a rolling 12 month period eg:
我试图返回一些分布在滚动 12 个月期间的结果，例如：
MONTH IN OUT
January 210 191
February 200 111
March 132 141
April 112 141
May 191 188
etc...
How do I spread the results over a date range, populating the first column with the month name?
如何将结果分布在一个日期范围内，用月份名称填充第一列？
IN MSSQL it would be something like:
在 MSSQL 中，它类似于：
SELECT COUNT(problem.problem_type = 'IN') AS IN,
COUNT(problem.problem_type = 'OUT') AS OUT,
DATEPART(year, DateTime) as Year,
DATEPART(month, DateTime) as Month
FROM problem
WHERE (DateTime >= dbo.FormatDateTime('2010-01-01'))
AND
(DateTime < dbo.FormatDateTime('2010-01-31'))
GROUP BY DATEPART(year, DateTime),
DATEPART(month, DateTime);
But this is against an Oracle database so DATEPART and DateTime are not available.
但这是针对 Oracle 数据库的，因此 DATEPART 和 DateTime 不可用。
My Problem table is roughly:
我的问题表大致是：
problem_ID Problem_type IN_Date OUT_Date
1 IN 2010-01-23 16:34:29.0 2010-02-29 13:06:28.0
2 IN 2010-01-27 12:34:29.0 2010-01-29 12:01:28.0
3 OUT 2010-02-13 13:24:29.0 2010-09-29 15:04:28.0
4 OUT 2010-02-15 16:31:29.0 2010-07-29 11:03:28.0
回答by OMG Ponies
Use:
用：
SELECT SUM(CASE WHEN p.problem_type = 'IN' THEN 1 ELSE 0 END) AS IN,
SUM(CASE WHEN p.problem_type = 'OUT' THEN 1 ELSE 0 END) AS OUT,
TO_CHAR(datetime, 'YYYY') AS year,
TO_CHAR(datetime, 'MM') AS month
FROM PROBLEM p
WHERE p.DateTime >= TO_DATE('2010-01-01', 'YYYY-MM-DD')
AND p.DateTime < TO_DATE('2010-01-31', 'YYYY-MM-DD')
GROUP BY TO_CHAR(datetime, 'YYYY'), TO_CHAR(datetime, 'MM')
You could also use:
您还可以使用：
SELECT SUM(CASE WHEN p.problem_type = 'IN' THEN 1 ELSE 0 END) AS IN,
SUM(CASE WHEN p.problem_type = 'OUT' THEN 1 ELSE 0 END) AS OUT,
TO_CHAR(datetime, 'MM-YYYY') AS mon_year
FROM PROBLEM p
WHERE p.DateTime >= TO_DATE('2010-01-01', 'YYYY-MM-DD')
AND p.DateTime < TO_DATE('2010-01-31', 'YYYY-MM-DD')
GROUP BY TO_CHAR(datetime, 'MM-YYYY')
Reference:
参考：
回答by Justin Cave
You probably want something like
你可能想要类似的东西
SELECT SUM( (CASE WHEN problem_type = 'IN' THEN 1 ELSE 0 END) ) in,
SUM( (CASE WHEN problem_type = 'OUT' THEN 1 ELSE 0 END) ) out,
EXTRACT( year FROM DateTime ) year,
EXTRACT( month FROM DateTime ) month
FROM problem
WHERE DateTime >= date '2010-01-01'
AND DateTime < date '2010-01-31'
GROUP BY EXTRACT( year FROM DateTime ),
EXTRACT( month FROM DateTime )
