Python 类型错误：“str”和“int”的实例之间不支持“<=”
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TypeError: '<=' not supported between instances of 'str' and 'int'
提问by Douglas da Silva
I'm learning python and working on exercises. One of them is to code a voting system to select the best player between 23 players of the match using lists.
我正在学习 python 并进行练习。其中之一是编写投票系统以使用列表在比赛的 23 名球员中选择最佳球员。
I'm using Python3.
我正在使用Python3.
My code:
我的代码：
players= [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
vote = 0
cont = 0
while(vote >= 0 and vote <23):
vote = input('Enter the name of the player you wish to vote for')
if (0 < vote <=24):
players[vote +1] += 1;cont +=1
else:
print('Invalid vote, try again')
I get
我得到
TypeError: '<=' not supported between instances of 'str' and 'int'
类型错误：“str”和“int”的实例之间不支持“<=”
But I don't have any strings here, all variables are integers.
但是我这里没有任何字符串，所有变量都是整数。
回答by X33
Change
改变
vote = input('Enter the name of the player you wish to vote for')
to
到
vote = int(input('Enter the name of the player you wish to vote for'))
You are getting the input from the console as a string, so you must cast that input string to an intobject in order to do numerical operations.
您从控制台以字符串形式获取输入，因此您必须将该输入字符串转换为int对象才能进行数值运算。
回答by McGrady
If you're using Python3.x inputwill return a string,so you should use intmethod to convert string to integer.
如果您使用的是 Python3.xinput将返回一个字符串，因此您应该使用int方法将字符串转换为整数。
If the prompt argument is present, it is written to standard output without a trailing newline. The function then reads a line from input, converts it to a string(stripping a trailing newline), and returns that. When EOF is read, EOFError is raised.
如果存在 prompt 参数，则将其写入标准输出，而没有尾随换行符。然后该函数从输入中读取一行， 将其转换为字符串（去除尾随的换行符），然后返回该字符串。读取 EOF 时，会引发 EOFError。
By the way,it's a good way to use trycatchif you want to convert string to int:
顺便说一句，trycatch如果您想将字符串转换为 int ，这是一个很好的使用方法：
try:
i = int(s)
except ValueError as err:
pass
Hope this helps.
希望这可以帮助。
回答by R. Mercy
When you use the input function it automatically turns it into a string. You need to go:
当您使用 input 函数时，它会自动将其转换为字符串。你需要去：
vote = int(input('Enter the name of the player you wish to vote for'))
which turns the input into a int type value
它将输入转换为 int 类型值
回答by Drool
input() by default takes the input in form of strings.
input() 默认采用字符串形式的输入。
if (0<= vote <=24):
vote takes a string input (suppose '4','5',etc) and becomes uncomparable.
投票需要一个字符串输入（假设'4'、'5'等）并且变得无法比较。
Correct way is : vote = int(input("Enter your message")will convert the input to integer ('4' to 4 or '5' to 5 depending on the input)
正确的方法是：vote = int(input("Enter your message")将输入转换为整数（'4' 到 4 或 '5' 到 5，具体取决于输入）
