bash 将变量与shell中的整数进行比较？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/18133161/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Compare variable with integer in shell?
提问by David Wright
I have an if statement I need to run, as long as the value I have stored in my $countervariable is greater than 5.
我有一个 if 语句需要运行，只要我存储在$counter变量中的值大于5.
Here is the respective section of my current (non-functioning) script:
这是我当前（非运行）脚本的相应部分：
if $counter > 5
then
echo "something"
fi
The mistake I'm making is probably very obvious, but for some reason I couldn't find the solution online.. Thanks!
我犯的错误可能很明显，但由于某种原因我无法在网上找到解决方案..谢谢！
回答by konsolebox
Well that is quite simple:
嗯，这很简单：
if [ "$counter" -gt 5 ]
then
echo "something"
fi
回答by Thomas
Arithmetic needs to be done between ((and )):
需要在((和之间进行算术运算))：
if (( $counter > 5 ))
Incidentally, you can also leave off the $in arithmetic, though it doesn't hurt to keep it.
顺便说一句，您也可以不使用$in 算术，尽管保留它并没有什么坏处。
