PHP 中意外的 T_VARIABLE 是什么？
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What is unexpected T_VARIABLE in PHP?
提问by omg
I get this PHP error:
我收到此 PHP 错误：
Parse error: syntax error, unexpected T_VARIABLE
解析错误：语法错误，意外的 T_VARIABLE
From this line:
从这一行：
$list[$i][$docinfo['attrs']['@groupby']] = $docinfo['attrs']['@count'];
Is there anything wrong with this line?
这条线有什么问题吗？
回答by knittl
There might be a semicolon or bracket missing a line before your pasted line.
在粘贴的行之前可能有一个分号或括号缺少一行。
It seems fine to me; every string is allowed as an array index.
对我来说似乎很好；每个字符串都允许作为数组索引。
回答by dusoft
It could be some other line as well. PHP is not always that exact.
它也可能是其他一些线路。PHP 并不总是那么精确。
Probably you are just missing a semicolon on previous line.
可能您只是在前一行中缺少一个分号。
How to reproduce this error, put this in a file called a.php:
如何重现此错误，请将其放在名为的文件中a.php：
<?php
$a = 5
$b = 7; // Error happens here.
print $b;
?>
Run it:
运行：
eric@dev ~ $ php a.php
PHP Parse error: syntax error, unexpected T_VARIABLE in
/home/el/code/a.php on line 3
Explanation:
解释：
The PHP parser converts your program to a series of tokens. A T_VARIABLEis a Token of type VARIABLE. When the parser processes tokens, it tries to make sense of them, and throws errors if it receives a variable where none is allowed.
PHP 解析器将您的程序转换为一系列标记。AT_VARIABLE是 VARIABLE 类型的令牌。当解析器处理标记时，它会尝试理解它们，如果它收到一个不允许的变量，则会抛出错误。
In the simple case above with variable $b, the parser tried to process this:
在上面带有变量的简单情况下$b，解析器尝试处理：
$a = 5 $b = 7;
The PHP parser looks at the $b after the 5 and says "that is unexpected".
PHP 解析器查看 5 之后的 $b 并说“这是出乎意料的”。
回答by Zank
In my case it was an issue of the PHP version.
就我而言，这是 PHP 版本的问题。
The .phar file I was using was not compatible with PHP 5.3.9. Switching interpreter to PHP 7 did fix it.
我使用的 .phar 文件与 PHP 5.3.9 不兼容。将解释器切换到 PHP 7 确实修复了它。
