未处理的异常 java.net.malformedurlexception
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unhandled exception java.net.malformedurlexception
提问by John
How come this code is giving me a unhandled exception java.net.malformedurlexceptionin java ?
这段代码怎么给了我一个unhandled exception java.net.malformedurlexceptionin java ？
String u = "http://webapi.com/demo.zip";
URL url = new URL(u);
Can someone tell me how to fix?
有人可以告诉我如何修复吗？
回答by Gerard Reches
You need to handle the posible exception.
您需要处理可能的异常。
Try with this:
试试这个：
try {
String u = "http://webapi.com/demo.zip";
URL url = new URL(u);
} catch (MalformedURLException e) {
e.printStackTrace();
}
回答by Zarwan
Use a try catch statement to handle exceptions:
使用 try catch 语句来处理异常：
String u = "http://webapi.com/demo.zip";
try {
URL url = new URL(u);
} catch (MalformedURLException e) {
//do whatever you want to do if you get the exception here
}
回答by hesham ahmed
java.net.malformedurlexception
It means that no legal protocol could be found in a specification string or the string could not be parsed or your URL is not confirmed the spec or missing a component I think this will help you to understand URL
这意味着在规范字符串中找不到合法的协议或字符串无法解析或您的 URL 未确认规范或缺少组件我认为这将帮助您理解 URL
