bash 脚本，创建目录中所有文件的数组
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bash script, create array of all files in a directory
提问by anonuser0428
I have a directory myDirof many .html files. I am trying to create an array of all the files in the directory so I might be able to index the array and be able to refer to particular html files in the directory. I have tried the following line:
我有一个myDir包含许多 .html 文件的目录。我正在尝试创建目录中所有文件的数组，以便我可以索引该数组并能够引用目录中的特定 html 文件。我尝试了以下行：
myFileNames=$(ls ~/myDir)
for file in $myFileNames;
#do something
but I want to be able to have a counter variable and have logic like the following:
但我希望能够拥有一个计数器变量并具有如下逻辑：
while $counter>=0;
#do something to myFileNames[counter]
I am quite new to shell scripting and am unable to figure out how to achieve this hence would appreciate any help regarding this matter.
我对 shell 脚本很陌生，无法弄清楚如何实现这一点，因此将感谢有关此事的任何帮助。
回答by anubhava
You can do:
你可以做：
# create an array with all the filer/dir inside ~/myDir
arr=(~/myDir/*)
# iterate through array using a counter
for ((i=0; i<${#arr[@]}; i++)); do
#do something to each element of array
echo "${arr[$i]}"
done
You can also do this for iteration of array:
您也可以为数组的迭代执行此操作：
for f in "${arr[@]}"; do
echo "$f"
done
回答by Paul Hicks
Your solution will work for generating the array. Instead of using a while loop, use a for loop:
您的解决方案将用于生成阵列。使用 for 循环而不是使用 while 循环：
#!/bin/bash
files=$( ls * )
counter=0
for i in $files ; do
echo Next: $i
let counter=$counter+1
echo $counter
done
