Javascript 根据内容过滤数组中的字符串
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Filter strings in Array based on content
提问by prince
I am running into an issue, I have a similar array of Strings in JS:
我遇到了一个问题，我在 JS 中有一个类似的字符串数组：
var myArray = ["bedroomone", "bedroomonetwo", "bathroom"];
And I would like to retrieve all the elements in the array that contains the keyword 'bedroom'. How can I achieve such result ?
我想检索包含关键字“卧室”的数组中的所有元素。我怎样才能达到这样的结果？
I tried in different ways without getting the desired result. How should I proceed ?
我尝试了不同的方法，但没有得到想要的结果。我应该如何进行？
回答by Microfed
var PATTERN = 'bedroom',
filtered = myArray.filter(function (str) { return str.indexOf(PATTERN) === -1; });
var PATTERN = /bedroom/,
filtered = myArray.filter(function (str) { return PATTERN.test(str); });
String.prototype.includes(only in moderm browsers):
String.prototype.includes（仅在现代浏览器中）：
var PATTERN = 'bedroom',
filtered = myArray.filter(function (str) { return str.includes(PATTERN); });
回答by Ania Zielinska
var bedrooms = myArray.filter(name => name.includes('bedroom'))
回答by Moh .S
Improved Microfed's answer to this
改进了 Microfed 对此的回答
var textToSearch = 'bedroom';
var filteredArray = myArray.filter((str)=>{
return str.toLowerCase().indexOf(textToSearch.toLowerCase()) >= 0;
});
回答by Ardenne
You could also use the search() method
您还可以使用 search() 方法
Finds the first substring match in a regular expression search.
(method) String.search(regexp: string | RegExp): number (+1 overload)
在正则表达式搜索中查找第一个子字符串匹配。
(方法) String.search(regexp: string | RegExp): number (+1 重载)
const filterList = (data, query) => {
return data.filter(name => name.toLowerCase().search(query.toLowerCase()) !== -1);
};
