C# 使用带有 Xml 命名空间的 Linq to Xml
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Use Linq to Xml with Xml namespaces
提问by Tim
I have this code :
我有这个代码：
/*string theXml =
@"<Response xmlns=""http://myvalue.com""><Result xmlns:a=""http://schemas.datacontract.org/2004/07/My.Namespace"" xmlns:i=""http://www.w3.org/2001/XMLSchema-instance""><a:TheBool>true</a:TheBool><a:TheId>1</a:TheId></Result></Response>";*/
string theXml = @"<Response><Result><TheBool>true</TheBool><TheId>1</TheId></Result></Response>";
XDocument xmlElements = XDocument.Parse(theXml);
var elements = from data in xmlElements.Descendants("Result")
select new {
TheBool = (bool)data.Element("TheBool"),
TheId = (int)data.Element("TheId"),
};
foreach (var element in elements)
{
Console.WriteLine(element.TheBool);
Console.WriteLine(element.TheId);
}
When I use the first value for theXml, the result is null, whereas with the second one, I have good values ...
当我为 theXml 使用第一个值时，结果为空，而使用第二个值时，我有很好的值......
How to use Linq to Xml with xmlns values ?
如何使用带有 xmlns 值的 Linq to Xml ？
采纳答案by Mike Two
LINQ to XML methods like Descendantsand Elementtake an XNameas an argument. There is a conversion from stringto XNamethat is happening automatically for you. You can fix this by adding an XNamespacebefore the strings in your Descendantsand Elementcalls. Watch out because you have 2 different namespaces at work.
LINQ to XML 方法，如Descendants并Element以 anXName作为参数。有一个从string到XName那个的转换正在为你自动发生。您可以通过XNamespace在Descendants和Element调用中的字符串之前添加一个来解决此问题。请注意，因为您有 2 个不同的命名空间在工作。
string theXml =
@"true1";
//string theXml = @"true1";
XDocument xmlElements = XDocument.Parse( theXml );
XNamespace ns = "http://myvalue.com";
XNamespace nsa = "http://schemas.datacontract.org/2004/07/My.Namespace";
var elements = from data in xmlElements.Descendants( ns + "Result" )
select new
{
TheBool = (bool) data.Element( nsa + "TheBool" ),
TheId = (int) data.Element( nsa + "TheId" ),
};
foreach ( var element in elements )
{
Console.WriteLine( element.TheBool );
Console.WriteLine( element.TheId );
}
Notice the use of ns in Descendantsand nsa in Elements
注意 ns inDescendants和 nsa in 的使用Elements
回答by Lachlan Roche
You can pass an XNamewith a namespace to Descendants()and Element(). When you pass a string to Descendants(), it is implicitly converted to an XName with no namespace.
您可以将带有命名空间的XName传递给Descendants()和Element()。当您将字符串传递给 Descendants() 时，它会被隐式转换为没有命名空间的 XName。
To create a XName in a namespace, you create a XNamespace and concatenate it to the element local-name (a string).
要在命名空间中创建 XName，您需要创建一个 XNamespace 并将其连接到元素 local-name（一个字符串）。
XNamespace ns = "http://myvalue.com";
XNamespace nsa = "http://schemas.datacontract.org/2004/07/My.Namespace";
var elements = from data in xmlElements.Descendants( ns + "Result")
select new
{
TheBool = (bool)data.Element( nsa + "TheBool"),
TheId = (int)data.Element( nsa + "TheId"),
};
There is also a shorthand form for creating a XName with a namespace via implicit conversion from string.
还有一种通过从字符串隐式转换来创建带有命名空间的 XName 的简写形式。
var elements = from data in xmlElements.Descendants("{http://myvalue.com}Result")
select new
{
TheBool = (bool)data.Element("{http://schemas.datacontract.org/2004/07/My.Namespace}TheBool"),
TheId = (int)data.Element("{http://schemas.datacontract.org/2004/07/My.Namespace}TheId"),
};
Alternatively, you could query against XElement.Name.LocalName.
var elements = from data in xmlElements.Descendants()
where data.Name.LocalName == "Result"
回答by dotNET
I found the following code to work fine for reading attributes with namespaces in VB.NET:
我发现以下代码可以很好地读取 VB.NET 中具有命名空间的属性：
MyXElement.Attribute(MyXElement.GetNamespaceOfPrefix("YOUR_NAMESPACE_HERE") + "YOUR_ATTRIB_NAME")
Hope this helps someone down the road.
希望这可以帮助某人在路上。
回答by mike nelson
I have several namespaces listed at the top of an XML document, I don't really care about which elements are from which namespace. I just want to get the elements by their names. I've written this extension method.
我在 XML 文档的顶部列出了几个命名空间，我并不真正关心哪些元素来自哪个命名空间。我只想按名称获取元素。我写了这个扩展方法。
/// <summary>
/// A list of XElement descendent elements with the supplied local name (ignoring any namespace), or null if the element is not found.
/// </summary>
public static IEnumerable<XElement> FindDescendants(this XElement likeThis, string elementName) {
var result = likeThis.Descendants().Where(ele=>ele.Name.LocalName==elementName);
return result;
}
