bash bash循环遍历所有子目录中的递归
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bash loop through all find recursively in sub-directories
提问by qwertymk
I have a bash script that looks like the following:
我有一个如下所示的 bash 脚本：
#!/bin/bash
FILES=public_html/*.php # */ stupid syntax highlighter!
for f in $FILES
do
echo "Processing $f file..."
# take action on each file.
done
Now I need it to go through all subdirectories in public_htmlso it should run on:
现在我需要它遍历所有子目录，public_html所以它应该运行：
/public_html/index.php
/public_html/forums/status.php
/public_html/really/deep/file/in/many/sub/dirs/here.php
What do I change FILES=public_html/*.phpto in order to do that?
FILES=public_html/*.php为了做到这一点，我要改变什么？
Also I need to check to make sure that there is at least one file or else it prints
我还需要检查以确保至少有一个文件，否则它会打印
Processing *.php file...
回答by sgibb
FILES=$(find public_html -type f -name '*.php')
IMPORTANT:Note the single quotes around the *.phpto prevent shell expansion of the *.
重要提示：注意周围的单引号*.php以防止*.
回答by Jarryd
FILES=`find public_html -type d`
$FILES will now be a list of every single directory inside public_html.
$FILES 现在将是 public_html 中每个目录的列表。
