Python 使用 paramiko 运行 Sudo 命令
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Running Sudo Command with paramiko
提问by user3176971
I am trying to execute a sudo command on a remote machine using python-paramiko, when I execute the command, I bind it with 3 streams, and I use the input stream to pass the password, but it doesn't work, this is the traceback result:
我正在尝试使用python-paramiko在远程机器上执行sudo命令，当我执行命令时，我将它与3个流绑定，并使用输入流传递密码，但它不起作用，这是回溯结果：
Traceback (most recent call last):
File "<input>", line 1, in <module>
File "/usr/local/lib/python2.7/dist-packages/paramiko/file.py", line 314, in write
self._write_all(data)
File "/usr/local/lib/python2.7/dist-packages/paramiko/file.py", line 439, in _write_all
count = self._write(data)
File "/usr/local/lib/python2.7/dist-packages/paramiko/channel.py", line 1263,in _write
self.channel.sendall(data)
File "/usr/local/lib/python2.7/dist-packages/paramiko/channel.py", line 796, in sendall
raise socket.error('Socket is closed')
error: Socket is closed
and this is my python code:
这是我的python代码：
import paramiko
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect('192.168.0.104', username='cdc',password='123456')
stdin, stdout, stderr = ssh.exec_command("sudo dmesg")
stdin.write("123456\n")
stdin.flush()
print stdout.readlines()
ssh.close()
Any help? Thanks in advance
有什么帮助吗？提前致谢
回答by stanleyxu2005
First of all, have you tried in console with ssh [email protected] "sudo -S -p '' dmesg". If it also fails, then you might check the sshdsettings and the sudoersettings.
首先，您是否尝试过在控制台中使用ssh [email protected] "sudo -S -p '' dmesg". 如果它也失败了，那么您可能会检查sshd设置和sudoer设置。
If it works well, please add some echo between lines, so that we can know exactly when the exception was thrown. I highly doubt that you should change sudo dmesgto sudo -S -p '' dmesg.
如果运行良好，请在行之间添加一些 echo，以便我们可以准确知道何时抛出异常。我非常怀疑您是否应该更改sudo dmesg为sudo -S -p '' dmesg.
You might also try my wrapper of paramiko. I can use it smoothly to access any CentOS/SuSE node and perform any commands (w/wo sudo privilege):
你也可以试试我的 paramiko 包装器。我可以流畅地使用它来访问任何 CentOS/SuSE 节点并执行任何命令（w/wo sudo 权限）：
#!/usr/bin/python
from StringIO import StringIO
import paramiko
class SshClient:
"A wrapper of paramiko.SSHClient"
TIMEOUT = 4
def __init__(self, host, port, username, password, key=None, passphrase=None):
self.username = username
self.password = password
self.client = paramiko.SSHClient()
self.client.set_missing_host_key_policy(paramiko.AutoAddPolicy())
if key is not None:
key = paramiko.RSAKey.from_private_key(StringIO(key), password=passphrase)
self.client.connect(host, port, username=username, password=password, pkey=key, timeout=self.TIMEOUT)
def close(self):
if self.client is not None:
self.client.close()
self.client = None
def execute(self, command, sudo=False):
feed_password = False
if sudo and self.username != "root":
command = "sudo -S -p '' %s" % command
feed_password = self.password is not None and len(self.password) > 0
stdin, stdout, stderr = self.client.exec_command(command)
if feed_password:
stdin.write(self.password + "\n")
stdin.flush()
return {'out': stdout.readlines(),
'err': stderr.readlines(),
'retval': stdout.channel.recv_exit_status()}
if __name__ == "__main__":
client = SshClient(host='host', port=22, username='username', password='password')
try:
ret = client.execute('dmesg', sudo=True)
print " ".join(ret["out"]), " E ".join(ret["err"]), ret["retval"]
finally:
client.close()
回答by gloomy.penguin
I know this question is kind of old but I was wanting to use sudo and paramiko together, too. It took me a while to figure out this solution. It may not work for everyone but I figured it was worth adding.
我知道这个问题有点老了，但我也想同时使用 sudo 和 paramiko。我花了一段时间才想出这个解决方案。它可能并不适合所有人，但我认为值得添加。
def ssh_handler(hostname, username=USER, password=PASS, command=CMD):
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect(hostname,
username=username,
password=password)
stdin, stdout, stderr = ssh.exec_command(prepare_command(command))
# stdin.write(password+'\n')
response = stdout.read()
ssh.close()
print response
def prepare_command(command):
if (not isinstance(command, basestring)):
command = ' ; '.join(command)
command = command.replace('"','\"')
command = 'sudo -s -- " '+command+' " \n'
return command
# kind of a dumb example but you get the point
mycmd = [];
mycmd.append('cd /dir/this/user/doesnt/have/access/to')
mycmd.append('ls -las')
mycmd.append('cat file_in_dir.txt')
ssh_handler(server, command=mycmd)
回答by AlexS
Im sorry i dont have time for details answer but i was able to implement sudo commands on paramiko using thisadvise
对不起，我没有时间详细回答，但我能够使用此建议在 paramiko 上实施 sudo 命令
#!/usr/bin/env python
import paramiko
l_password = "yourpassword"
l_host = "yourhost"
l_user = "yourusername"
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect(l_host, username=l_user, password=l_password)
transport = ssh.get_transport()
session = transport.open_session()
session.set_combine_stderr(True)
session.get_pty()
#for testing purposes we want to force sudo to always to ask for password. because of that we use "-k" key
session.exec_command("sudo -k dmesg")
stdin = session.makefile('wb', -1)
stdout = session.makefile('rb', -1)
#you have to check if you really need to send password here
stdin.write(l_password +'\n')
stdin.flush()
for line in stdout.read().splitlines():
print 'host: %s: %s' % (l_host, line)
