ios 如何检测 NSString 是否包含特定字符？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/14266059/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to detect if NSString contains a particular character or not?
提问by Sim Fox
i have one NSString object , for ex:- ($45,0000)
我有一个 NSString 对象，例如：- ($45,0000)
Now i want to find if this string contains () or not
现在我想找出这个字符串是否包含 ()
How can i do this?
我怎样才能做到这一点？
回答by Lily Ballard
Are you trying to find if it contains at least one of (or )? You can use -rangeOfCharacterFromSet::
您是否正在尝试查找它是否至少包含(或 之一)？您可以使用-rangeOfCharacterFromSet:：
NSCharacterSet *cset = [NSCharacterSet characterSetWithCharactersInString:@"()"];
NSRange range = [mystr rangeOfCharacterFromSet:cset];
if (range.location == NSNotFound) {
// no ( or ) in the string
} else {
// ( or ) are present
}
回答by dloomb
The method below will return Yes if the given string contains the given char
如果给定的字符串包含给定的字符，下面的方法将返回 Yes
-(BOOL)doesString:(NSString *)string containCharacter:(char)character
{
return [string rangeOfString:[NSString stringWithFormat:@"%c",character]].location != NSNotFound;
}
You can use it as follows:
您可以按如下方式使用它：
NSString *s = @"abcdefg";
if ([self doesString:s containCharacter:'a'])
NSLog(@"'a' found");
else
NSLog(@"No 'a' found");
if ([self doesString:s containCharacter:'h'])
NSLog(@"'h' found");
else
NSLog(@"No 'h' found");
Output:
输出：
2013-01-11 11:15:03.830 CharFinder[17539:c07] 'a' found
2013-01-11 11:15:03.830 CharFinder [17539:c07] 'a' 发现
2013-01-11 11:15:03.831 CharFinder[17539:c07] No 'h' found
2013-01-11 11:15:03.831 CharFinder[17539:c07] 没有找到“h”
回答by Christian Hartmann
- (bool) contains: (NSString*) substring {
NSRange range = [self rangeOfString:substring];
return range.location != NSNotFound;
}
回答by Rahul Mathur
I got a generalized answer to your question which I was using in my code. This code includes the following rules: 1. No special characters 2. At least one capital and one small English alphabet 3. At least one numeric digit
我在我的代码中使用了您的问题的一般答案。此代码包括以下规则： 1. 无特殊字符 2. 至少一个大写字母和一个小英文字母 3. 至少一个数字
BOOL lowerCaseLetter,upperCaseLetter,digit,specialCharacter;
int asciiValue;
if([txtPassword.text length] >= 5)
{
for (int i = 0; i < [txtPassword.text length]; i++)
{
unichar c = [txtPassword.text characterAtIndex:i];
if(!lowerCaseLetter)
{
lowerCaseLetter = [[NSCharacterSet lowercaseLetterCharacterSet] characterIsMember:c];
}
if(!upperCaseLetter)
{
upperCaseLetter = [[NSCharacterSet uppercaseLetterCharacterSet] characterIsMember:c];
}
if(!digit)
{
digit = [[NSCharacterSet decimalDigitCharacterSet] characterIsMember:c];
}
asciiValue = [txtPassword.text characterAtIndex:i];
NSLog(@"ascii value---%d",asciiValue);
if((asciiValue >=33&&asciiValue < 47)||(asciiValue>=58 && asciiValue<=64)||(asciiValue>=91 && asciiValue<=96)||(asciiValue>=91 && asciiValue<=96))
{
specialCharacter=1;
}
else
{
specialCharacter=0;
}
}
if(specialCharacter==0 && digit && lowerCaseLetter && upperCaseLetter)
{
//do what u want
NSLog(@"Valid Password %d",specialCharacter);
}
else
{
NSLog(@"Invalid Password %d",specialCharacter);
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error"
message:@"Please Ensure that you have at least one lower case letter, one upper case letter, one digit and No Any special character"
delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
}
回答by Pravin Kamble
Why to always use for NSCharactorSet ?? this is simple and powerful solution
为什么总是使用 NSCharactorSet ？？这是简单而强大的解决方案
NSString *textStr = @"This is String Containing / Character";
if ([textStr containsString:@"/"])
{
NSLog(@"Found!!");
}
else
{
NSLog(@"Not Found!!");
回答by Alex Obenauer
You can use
您可以使用
NSString rangeOfString: (NSString *) string
请参阅此处：https: //developer.apple.com/library/mac/#documentation/Cocoa/Reference/Foundation/Classes/NSString_Class/Reference/NSString.html%23//apple_ref/occ/instm/NSString/rangeOfString：
If the NSRange comes back with property 'location' equal to NSNotFound, then the string does not contain the passed string (or character).
如果 NSRange 返回的属性“location”等于 NSNotFound，则该字符串不包含传递的字符串（或字符）。
