bash Word Unexpected (expecting ")") 与 Makefile
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Word Unexpected (expecting ")") with Makefile
提问by Wuzseen
I'm making a makefile and I'm working on a target with no dependencies that checks to see if a file named README exists in the current directory and if it does, read it using less or else exit quitely: give no errors whatsoever--the command to run the target should print nothing to console if this is the case.
我正在制作一个 makefile 并且我正在处理一个没有依赖项的目标，该目标检查当前目录中是否存在名为 README 的文件，如果存在，则使用 less 读取它或完全退出：不要出现任何错误- - 在这种情况下，运行目标的命令不应向控制台打印任何内容。
I've tried a couple different ways but nothing really seems to work (PAGER is simply a var equal to less):
我尝试了几种不同的方法，但似乎没有任何效果（PAGER 只是一个等于 less 的 var）：
read :
ifneq ("$(wildcard README)","")
-@$(PAGER) README
endif
And also with this code
还有这个代码
read :
-@for file in *;\
do \
if [ ${file} == "README" ]; then\
$(PAGER) "README" ;\
fi;\
done
With the first chunk I keep getting an error akin to /bin/sh: Syntax error: word unexpected (expecting ")") and for the life of me I just don't get what it's saying. I certainly don't think there's a syntax error, perhaps I'm misusing make.
对于第一个块，我不断收到类似于 /bin/sh: Syntax error: word unexpected (expecting ")") 的错误，而在我的一生中，我只是不明白它在说什么。我当然不认为有语法错误，也许我在滥用 make。
For the latter code I get an unexpected operator error for the ==.
对于后面的代码，我收到了一个意外的 == 操作符错误。
I've also tried simpler things like these two single liner solutions but get similar errors:
我也尝试过更简单的事情，比如这两个单线解决方案，但得到了类似的错误：
-@test -a README && less README
-@[ -a README ] && less README
Any help would be greatly appreciated.
任何帮助将不胜感激。
EDIT: I was digging further and saw something promising and explicitly setting my shell to /bin/bash (SHELL := /bin/bash) yet no dice.
编辑：我正在进一步挖掘，看到了一些有希望的东西，并明确地将我的 shell 设置为 /bin/bash (SHELL := /bin/bash) 但没有骰子。
采纳答案by Beta
read:
@if [ -e README ]; then less README; fi
回答by npclaudiu
You should try to extract your shell code in separate *.sh files so that you can specify them as commands in your makefile (and make sure that the *.sh files are executable).
您应该尝试在单独的 *.sh 文件中提取您的 shell 代码，以便您可以在 makefile 中将它们指定为命令（并确保 *.sh 文件是可执行的）。
