C# 挥动鼠标
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Wiggling the mouse
提问by Bruce the Hoon
OK. This is a bit of a vanity app, but I had a situation today at work where I was in a training class and the machine was set to lock every 10 minutes. Well, if the trainers got excited about talking - as opposed to changing slides - the machine would lock up.
好的。这是一个有点虚荣的应用程序，但我今天在工作中遇到了一个情况，我在培训班上，机器被设置为每 10 分钟锁定一次。好吧，如果培训师对谈话感到兴奋——而不是更换滑梯——机器就会锁死。
I'd like to write a teeny app that has nothing but a taskbar icon that does nothing but move the mouse by 1 pixel every 4 minutes.
我想编写一个很小的应用程序，它只有一个任务栏图标，除了每 4 分钟将鼠标移动 1 个像素外什么都不做。
I can do that in 3 ways with Delphi (my strong language) but I'm moving to C# for work and I'd like to know the path of least resistance there.
我可以用 Delphi（我的强语言）以 3 种方式做到这一点，但我正在转向 C# 工作，我想知道那里阻力最小的路径。
采纳答案by lubos hasko
for C# 3.5
对于 C# 3.5
without notifyicon therefore you will need to terminate this application in task manager manually
没有通知图标，因此您需要在任务管理器中手动终止此应用程序
using System;
using System.Drawing;
using System.Windows.Forms;
static class Program
{
static void Main()
{
Timer timer = new Timer();
// timer.Interval = 4 minutes
timer.Interval = (int)(TimeSpan.TicksPerMinute * 4 / TimeSpan.TicksPerMillisecond);
timer.Tick += (sender, args) => { Cursor.Position = new Point(Cursor.Position.X + 1, Cursor.Position.Y + 1); };
timer.Start();
Application.Run();
}
}
回答by DylanJ
Something like this should work (though, you willwant to change the interval).
像这样的东西应该工作（虽然，你会想改变的时间间隔）。
public Form1()
{
InitializeComponent();
Timer Every4Minutes = new Timer();
Every4Minutes.Interval = 10;
Every4Minutes.Tick += new EventHandler(MoveNow);
Every4Minutes.Start();
}
void MoveNow(object sender, EventArgs e)
{
Cursor.Position = new Point(Cursor.Position.X - 1, Cursor.Position.Y - 1);
}
回答by Zooba
The "correct" way to do this is to respond to the WM_SYSCOMMAND message. In C# this looks something like this:
执行此操作的“正确”方法是响应 WM_SYSCOMMAND 消息。在 C# 中，这看起来像这样：
protected override void WndProc(ref Message m)
{
// Abort screensaver and monitor power-down
const int WM_SYSCOMMAND = 0x0112;
const int SC_MONITOR_POWER = 0xF170;
const int SC_SCREENSAVE = 0xF140;
int WParam = (m.WParam.ToInt32() & 0xFFF0);
if (m.Msg == WM_SYSCOMMAND &&
(WParam == SC_MONITOR_POWER || WParam == SC_SCREENSAVE)) return;
base.WndProc(ref m);
}
According to MSDN, if the screensaver password is enabled by policy on Vista or above, this won't work. Presumably programmatically moving the mouse is also ignored, though I have not tested this.
根据MSDN，如果在 Vista 或更高版本上通过策略启用了屏幕保护程序密码，这将不起作用。据推测，以编程方式移动鼠标也被忽略，尽管我没有对此进行测试。
回答by Heywoody
When I work from home, I do this by tying the mouse cord to a desktop fan which oscillates left to right. It keeps the mouse moving and keeps the workstation from going to sleep.
当我在家工作时，我将鼠标线系在一个左右摆动的桌面风扇上。它使鼠标保持移动并防止工作站进入睡眠状态。
