VB.NET Select Case - 正确的说法是什么？
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VB.NET Select Case - what is the correct statement?
提问by Brandon
Why doesn't the following code work?
为什么下面的代码不起作用？
Private Function resolveSiteName(ByVal plantName As String, ByVal siteName As String) As Integer
Dim siteId As Integer = Nothing
Dim fullName As String = plantName & siteName
Select Case fullName
Case fullName.Contains("Example" And "Example2" And "Example3")
siteId = 0
End Select
Return siteId
End Function
I'm guessing my Select Case fullNameis wrong, because when debugging it, the conditions are met and it just skips over assigning the siteId.
我猜我Select Case fullName是错的，因为在调试它时，条件得到满足，它只是跳过分配siteId.
I also tried just this
我也试过这个
Case fullName.Equals("Exactly what full name is")
just to test to see if that would work...and it still skipped over the assigning part.
只是为了测试看看这是否有效......它仍然跳过了分配部分。
What am I missing here?
我在这里错过了什么？
回答by Ric
This should work too:
这也应该有效：
Select Case fullName
Case "Example", "Example2", "Example3"
siteId = 0
End Select
回答by Tim Schmelter
Note that this would not even compile if you'd use an If-clause(which is more appropriate here):
请注意，如果您使用If-clause（这里更合适），这甚至不会编译：
If fullName.Contains("Example" And "Example2" And "Example3") Then
' this doesn't compile since you cannot concat a string with And
' you want to check if fullName equals to one of the strings anyway
siteId = 0
End If
If you want to check multiple items at once, define a collection, add all to it and then use Contains:
如果要一次检查多个项目，请定义一个集合，将所有项添加到其中，然后使用Contains：
Dim siteNames = { "Example", "Example2", "Example3" }
If siteNames.Contains(fullName) Then
siteId = 0
End If
回答by Steven Ackley
Try this:
尝试这个：
Select Case fullName
Case "Example"
siteId = 0
Case "Example2"
siteId = 0
Case "Example3"
siteId = 0
End Select
回答by SysDragon
This solves your problem:
这可以解决您的问题：
Select Case True
Case fullName.Contains("Example")
siteId = 0
End Select
Or for your second try:
或者您的第二次尝试：
Select Case fullName
Case "Exactly what full name is"
siteId = 0
End Select
回答by Isaac Ali
Replace
代替
Select Case fullName
with
和
Select Case True
