javax.xml.bind.UnmarshalException: 意外元素 (uri:""

javax.xml.bind.UnmarshalException: unexpected element (uri:""

提问by Ethan

I am getting an exception while turning an XML response from a service to a POJO. The XML looks like this:

将 XML 响应从服务转换为 POJO 时出现异常。XML 如下所示：

Here is my XML response.

这是我的XML 响应。

javax.xml.bind.UnmarshalException: unexpected element (uri:""
, local:"ItemSearchResponse"). Expected elements are
<{http://webservices.amazon.com/AWSECommerceService/2011-08-01}ItemSearchResponse>

I am using it like this:

我是这样使用它的：

 Document response = getResponse(url);
 JAXBContext context = JAXBContext.newInstance(AmazonItem.class);
 Unmarshaller unMarshaller = context.createUnmarshaller();
 newItem = (AmazonItem) unMarshaller.unmarshal(response);

Below are the details of my files

以下是我的文件的详细信息

package-info.java

包信息.java

@XmlSchema(
        namespace = "http://webservices.amazon.com/AWSECommerceService/2011-08-01",
        elementFormDefault = XmlNsForm.QUALIFIED)

package com.services.amazon;


import javax.xml.bind.annotation.XmlNsForm;
import javax.xml.bind.annotation.XmlSchema;

AmazonItem.java

亚马逊商品.java

@XmlRootElement(name="ItemSearchResponse")
@XmlAccessorType(XmlAccessType.FIELD)
public class AmazonItem
{
    @XmlElement(name="Items")
    private Items items = null;
}

Items.java

项目.java

@XmlAccessorType(XmlAccessType.FIELD)
public class Items { 
    @XmlElement(name="Item")
    List<Item> items = new ArrayList();
}

Item.java

项目.java

@XmlAccessorType(XmlAccessType.FIELD)
public class Item {
    @XmlElement(name="ASIN")
    private String asin;

    @XmlElement(name="ItemAttributes")
    private ItemAttributes attributes;

    @XmlElement(name="ItemLinks")
    private List<ItemLinks> itemLinks;
}

ItemAttributes.java

项目属性.java

@XmlAccessorType(XmlAccessType.FIELD)
public class ItemAttributes {
    @XmlElement(name="Title")
    private String title;

    @XmlElement(name="Actor")
    private List<String> actor;

    @XmlElement(name="ProductGroup")
    private String productGroup;
}

ItemLink.java

项目链接.java

@XmlAccessorType(XmlAccessType.FIELD)
public class ItemLink {
    @XmlElement(name="Description")
    private String description;

    @XmlElement(name="URL")
    private String url;
}

ItemLinks.java

项目链接.java

@XmlAccessorType(XmlAccessType.FIELD)
public class ItemLinks {
    @XmlElement(name="ItemLink")
    List<ItemLink> itemLinks;
}

回答by bdoughan

The error message is saying that you are getting an XML document that looks like this:

错误消息是说您正在获取一个如下所示的 XML 文档：

<ItemSearchResponse>

Instead of one like the following that matches the namespace qualification that you have mapped:

而不是与您已映射的命名空间限定匹配的以下内容：

<ItemSearchResponse xmlns="http://webservices.amazon.com/AWSECommerceService/2011-08-01">

回答by hoaz

The explanation is here: The JAXBContext instance is intialized with class(es) passed as parameter(s) and classes that are statically reachable from these class(es).

解释在这里：JAXBContext 实例初始化为作为参数传递的类和可以从这些类静态访问的类。

Initialize JAXBContextusing package, so it can see @XmlSchemadeclared in package-info.java:

JAXBContext使用 package初始化，所以可以看到@XmlSchemapackage-info.java 中声明的：

JAXBContext.newInstance("com.services.amazon")

回答by dmarwick

If you're using DocumentBuilderFactory in your getResponse method, try setting namespace awareness:

如果您在 getResponse 方法中使用 DocumentBuilderFactory，请尝试设置命名空间感知：

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware(true);

I had the same UnmarshalException and this solved it.

我有相同的 UnmarshalException，这解决了它。

回答by Stack overflow user

Remove the namespace from package-info.javaand change

从中删除命名空间package-info.java并更改

elementFormDefault = javax.xml.bind.annotation.XmlNsForm.QUALIFIED 

to

到

elementFormDefault = javax.xml.bind.annotation.XmlNsForm.UNQUALIFIED.

回答by Daísa Fernandes

Remove the namespace from package-info.java It's work for me

从 package-info.java 中删除命名空间它对我有用

Ex:

前任：

@javax.xml.bind.annotation.XmlSchema(namespace = "", elementFormDefault = javax.xml.bind.annotation.XmlNsForm.QUALIFIED)