C# 正则表达式非贪婪（懒惰）
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Regex Non-Greedy (Lazy)
提问by steventnorris
I'm attempting to non-greedily parse out TD tags. I'm starting with something like this:
我试图非贪婪地解析出 TD 标签。我从这样的事情开始：
<TD>stuff<TD align="right">More stuff<TD align="right>Other stuff<TD>things<TD>more things
I'm using the below as my regex:
我使用以下作为我的正则表达式：
Regex.Split(tempS, @"\<TD[.\s]*?\>");
The records return as below:
记录返回如下：
""
"stuff<TD align="right">More stuff<TD align="right>Other stuff"
"things"
"more things"
Why is it not splitting that first full result (the one starting with "stuff")? How can I adjust the regex to split on all instances of the TD tag with or without parameters?
为什么不拆分第一个完整结果（以“stuff”开头的结果）？如何调整正则表达式以在带或不带参数的 TD 标记的所有实例上拆分？
采纳答案by Chris Seymour
The regex you want is <TD[^>]*>:
你想要的正则表达式是<TD[^>]*>：
< # Match opening tag
TD # Followed by TD
[^>]* # Followed by anything not a > (zero or more)
> # Closing tag
Note: .matches anything (including whitespace) so [.\s]*?is redundant and wrong as [.]matches a literal .so use .*?.
注意：.匹配任何内容（包括空格），因此与文字匹配[.\s]*?是多余和错误的，因此请使用.[.]..*?
回答by Jason
For non greedy match, try this <TD.*?>
对于非贪婪匹配，试试这个 <TD.*?>
回答by Bastien Vandamme
*Quantifier — Matches between zero and unlimited times, as many times as possible, giving back as needed (greedy)*?Quantifier — Matches between zero and unlimited times, as few times as possible, expanding as needed (lazy)
*量词 - 在零次和无限次之间匹配，尽可能多次，根据需要回馈（贪婪）*?量词 - 在零次和无限次之间匹配，尽可能少，根据需要扩展（懒惰）
