ruby regex - 如何匹配所有字符直到字符 -
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ruby regex - how to match everything up till the character -
提问by TheExit
given a string as follow:
给定一个字符串，如下所示：
randomstring1-randomstring2-3df83eeff2
How can I use a ruby regex or some other ruby/rails friendly method to find everything up until the first dash -
我如何使用 ruby 正则表达式或其他一些 ruby/rails 友好的方法来查找所有内容，直到第一个破折号 -
In the example above that would be: randomstring1
在上面的例子中，这将是：randomstring1
Thanks
谢谢
回答by Kirill Polishchuk
You can use this pattern: ^[^\-]*
您可以使用此模式： ^[^\-]*
回答by agent-j
mystring = "randomstring1-randomstring2-3df83eeff2"
firstPart = mystring[0, mystring.index("-")]
Otherwise, I think the best regex is @polishchuk's.
否则，我认为最好的正则表达式是@polishchuk's。
It matches from the beginning of the string, matches as many as possible of anything that is not a dash -.
它从字符串的开头匹配，匹配尽可能多的不是 dash 的任何内容-。
回答by Pash
Using irb you can do this too:
使用 irb 你也可以这样做：
>> a= "randomstring1-randomstring2-3df83eeff2"
=> "randomstring1-randomstring2-3df83eeff2"
>> a.split('-').first
=> "randomstring1"
>>
回答by Mark Wilkins
For this situation, the index solution given by agent-j is probably better. If you did want to use regular expressions, the following non-greedy (specified by the ?) regex would grab it:
对于这种情况，agent-j 给出的索引解决方案可能会更好。如果您确实想使用正则表达式，以下非贪婪（由 指定?）正则表达式将获取它：
(^.*?)-
You can see it in Rubular.
您可以在Rubular 中看到它。
