PHP DOM：getElementsbyTagName
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PHP DOM : getElementsbyTagName
提问by Morph
I fear that this is a really stupid question but I am really stuck after trying a load of combinations for the last 2 hours. I am trying to pull the NAME out of the XML file
我担心这是一个非常愚蠢的问题，但在过去 2 小时内尝试了大量组合后，我真的被困住了。我正在尝试从 XML 文件中提取 NAME
My XML file:
我的 XML 文件：
<?xml version="1.0"?>
<userdata>
<name>John</name>
</userdata>
My php:
我的PHP：
$doc = new DOMDocument();
$doc -> load( "thefile.xml" );
$thename = $doc -> getElementsByTagName( "name" );
$myname= $thename -> getElementsByTagName("name") -> item(0) -> nodeValue;
The Error:
错误：
Catchable fatal error: Object of class DOMElement could not be converted to string in phpreader.php
I have tried
我试过了
$myname= $thename -> getElementsByTagName("name") -> item(0) ;
$myname= $doc -> getElementsByTagName("name") -> item(0) -> nodeValue;
$myname= $doc -> getElementsByTagName("name") -> item(0) ;
but all fail. Guess I have tried just about every combination except the correct one :(
但都失败了。猜猜我已经尝试过除了正确的组合之外的所有组合:(
回答by Federico Lebrón
You may want $myname = $thename->item(0)->nodeValue. $thename is already the NodeList of all of the nodes whose tag is "name" - you want the first item of these (->item(0)), and you want the value of the node (->nodeValue). $thenameshould be more appropriately named $names, and you'd see why $names->item(0)->nodeValuemakes sense semantically.
你可能想要$myname = $thename->item(0)->nodeValue。$thename 已经是其标签为“name”的所有节点的 NodeList - 您需要这些节点中的第一项 ( ->item(0))，并且需要节点的值 ( ->nodeValue)。$thename应该更恰当地命名$names，你会明白为什么$names->item(0)->nodeValue在语义上有意义。
This Works For MeTM.
这对我有用 TM。
回答by Morph
This code run:
此代码运行：
<?php
$xml = <<<XML
<?xml version="1.0"?>
<userdata>
<name>John</name>
</userdata>
XML;
$doc = new DOMDocument();
$doc->loadXML($xml);
$names = $doc->firstChild->getElementsByTagName("name");
$myname = $names->item(0)->nodeValue;
var_dump($myname);
