Python 查找列表中的每个第 n 个元素
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Finding every nth element in a list
提问by iKyriaki
How can I find every nth element of a list?
如何找到列表的每个第 n 个元素？
For a list [1,2,3,4,5,6], returnNth(l,2)should return [1,3,5]and for a list ["dog", "cat", 3, "hamster", True], returnNth(u,2)should return ['dog', 3, True]. How can I do this?
对于列表[1,2,3,4,5,6]，returnNth(l,2)应该返回[1,3,5]，对于列表["dog", "cat", 3, "hamster", True]，returnNth(u,2)应该返回['dog', 3, True]。我怎样才能做到这一点？
采纳答案by us2012
You just need lst[::n].
你只需要lst[::n].
Example:
例子：
>>> lst=[1,2,3,4,5,6,7,8,9,10]
>>> lst[::3]
[1, 4, 7, 10]
>>>
回答by avasal
In [119]: def returnNth(lst, n):
.....: return lst[::n]
.....:
In [120]: returnNth([1,2,3,4,5], 2)
Out[120]: [1, 3, 5]
In [121]: returnNth(["dog", "cat", 3, "hamster", True], 2)
Out[121]: ['dog', 3, True]
回答by sufinsha
I you need the every nth element....
我需要每个第 n 个元素....
def returnNth(lst, n):
# 'list ==> list, return every nth element in lst for n > 0'
return lst[::n]
