Javascript 字符串的 JQuery 过滤器编号
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JQuery Filter Numbers Of A String
提问by Tomkay
How do you filter only the numbers of a string?
如何仅过滤字符串的数字？
Example Pseudo Code:
number = $("thumb32").filternumbers()
number = 32
回答by Jonathon Bolster
You don't need jQuery for this - just plain old JavaScript regex replacement
你不需要 jQuery - 只是简单的旧 JavaScript正则表达式替换
var number = yourstring.replace(/[^0-9]/g, '')
var number = yourstring.replace(/[^0-9]/g, '')
This will get rid of anything that's not [0-9]
这将摆脱任何不是 [0-9]
Edit: Here's a small function to extract all the numbers (as actual numbers) from an input string. It's not an exhaustive expression but will be a good start for anyone needing.
编辑：这是一个从输入字符串中提取所有数字（作为实际数字）的小函数。这不是一个详尽的表达，但对于任何需要的人来说都是一个好的开始。
function getNumbers(inputString){
var regex=/\d+\.\d+|\.\d+|\d+/g,
results = [],
n;
while(n = regex.exec(inputString)) {
results.push(parseFloat(n[0]));
}
return results;
}
var data = "123.45,34 and 57. Maybe add a 45.824 with 0.32 and .56"
console.log(getNumbers(data));
// [123.45, 34, 57, 45.824, 0.32, 0.56];
回答by Pointy
Not really jQuery at all:
根本不是真正的jQuery：
number = number.replace(/\D/g, '');
That regular expression, /\D/g, matches any non-digit. Thus the call to .replace()replaces all non-digits (all of them, thanks to "g") with the empty string.
该正则表达式/\D/g匹配任何非数字。因此，调用以.replace()空字符串替换所有非数字（所有这些，感谢“g”）。
edit— if you want an actual *numbervalue, you can use parseInt()after removing the non-digits from the string:
编辑——如果你想要一个实际的 *数字值，你可以parseInt()在从字符串中删除非数字后使用：
var number = "number32"; // a string
number = number.replace(/\D/g, ''); // a string of only digits, or the empty string
number = parseInt(number, 10); // now it's a numeric value
If the original string may have no digits at all, you'll get the numeric non-value NaNfrom parseIntin that case, which may be as good as anything.
如果原始字符串可能根本没有数字，你会得到的数字非价值NaN从parseInt在这种情况下，这可能是一样好东西。
