Android 在 IntentService 中创建的 Toast 永远不会消失
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Toast created in an IntentService never goes away
提问by jax
I have an IntentService that downloads some files. The problem is that I create a Toast inside the IntentService like this
我有一个 IntentService 可以下载一些文件。问题是我像这样在 IntentService 中创建了一个 Toast
Toast.makeText(getApplicationContext(), "some message", Toast.LENGTH_SHORT).show();
The Toast will never disappear event if I exit the app. The only way to destroy it is to kill the process.
如果我退出应用程序，Toast 永远不会消失事件。破坏它的唯一方法是终止进程。
What am I doing wrong?
我究竟做错了什么？
采纳答案by Rich Schuler
You shouldn't create Toasts from a Service. You should use a Notificationinstead.
你不应该Toast从 a创建s Service。你应该使用 aNotification代替。
回答by rony l
The problem is that IntentServiceis not running on the main application thread. you need to obtain a Handlerfor the main thread (in onCreate()) and post the Toastto it as a Runnable.
问题是IntentService没有在主应用程序线程上运行。您需要Handler为主线程（in onCreate()）获取 a并将Toast其作为Runnable.
the following code should do the trick:
以下代码应该可以解决问题：
@Override
public void onCreate() {
super.onCreate();
mHandler = new Handler();
}
@Override
protected void onHandleIntent(Intent intent) {
mHandler.post(new Runnable() {
@Override
public void run() {
Toast.makeText(MyIntentService.this, "Hello Toast!", Toast.LENGTH_LONG).show();
}
});
}
回答by Ton
This works for me:
这对我有用：
public void ShowToastInIntentService(final String sText) {
final Context MyContext = this;
new Handler(Looper.getMainLooper()).post(new Runnable() {
@Override
public void run() {
Toast toast1 = Toast.makeText(MyContext, sText, Toast.LENGTH_LONG);
toast1.show();
}
});
};
回答by bluesway
IntentService will create a thread to handle the new intent, and terminated it immediately once the task has done. So, the Toast will be out of controlled by a dead thread.
IntentService 将创建一个线程来处理新的意图，并在任务完成后立即终止它。因此，Toast 将不受死线程的控制。
You should see some exceptions in the console when the toast showing on the screen.
当 Toast 显示在屏幕上时，您应该会在控制台中看到一些异常。
回答by Bugs Happen
For people developing in Xamarin studio, this is how its done there:
对于在 Xamarin 工作室开发的人来说，这是在那里完成的：
Handler handler = new Handler ();
handler.Post (() => {
Toast.MakeText (_Context, "Your text here.", ToastLength.Short).Show ();
});
回答by Daniel De León
To show a toast when the user is in one of the application activity.
当用户处于应用程序活动之一时显示祝酒词。
Just need a reference of the current activity, and call it with this sample code:
只需要当前活动的引用，并使用以下示例代码调用它：
public void showToast(final String msg) {
final Activity a = currentActivity;
if (a != null ) {
a.runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(a, msg, Toast.LENGTH_SHORT).show();
}
});
}
}
There is a lot of options to get the current activity, check this question: How to get current foreground activity context in android?
有很多选项可以获取当前活动，请检查这个问题： 如何在 android 中获取当前的前台活动上下文？
But I use this approach:
但我使用这种方法：
The application must have:
该应用程序必须具有：
private Activity currentActivity = null;
public Activity getCurrentActivity() {
return currentActivity;
}
public void setCurrentActivity(Activity mCurrentActivity) {
this.currentActivity = mCurrentActivity;
}
Each activity must have:
每项活动必须具有：
@Override
protected void onResume() {
super.onResume();
((MyApplication) getApplication()).setCurrentActivity(this);
}
@Override
protected void onPause() {
super.onPause();
((MyApplication) getApplication()).setCurrentActivity(null);
}
