php 使用数组的 Doctrine 查询生成器
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Doctrine Query Builder using Array
提问by Mick
I have an array of id:
我有一个 id 数组：
Id_array; //array(2) { [0]=> int(9) [1]=> int(10) }
I simply want to select the users using Id_array; I managed to do this when I don't have an array but just an integer:
我只想使用 Id_array 选择用户；当我没有数组而只有整数时，我设法做到了这一点：
$query = $em->createQuery('SELECT u FROM Users u WHERE u.id = ?1');
$query->setParameter(1, 9); // I tested the value 9 here
$users = $query->getResult();
How can I fetch all the users that correspond to Id_array?
如何获取与 Id_array 对应的所有用户？
回答by ZolaKt
Or without the query builder:
或者没有查询构建器：
$query = $em->createQuery('SELECT u FROM Users u WHERE u.id IN (:id)');
$query->setParameter('id', array(1, 9));
$users = $query->getResult();
回答by gagarine
On doctrine 2 is implemented by the repository now since 2.1 or 2.2
从 2.1 或 2.2 开始，现在由存储库实施了学说 2
findBy(array('id' => array(1, 2, 3, 4, 5));
回答by Mick
In case someone runs into something similar, I used the query builder, The key point is to use the IN statement.
如果有人遇到类似的情况，我使用了查询构建器，关键是使用 IN 语句。
//...
$qb = $this->createQueryBuilder('u');
$qb->add('where', $qb->expr()->in('u.id', ':my_array'))
->setParameter('my_array', $Id_array);
