Python 获取lxml中元素的内部HTML
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Get the inner HTML of a element in lxml
提问by Sudip Kafle
I am trying to get the HTML content of child node with lxml and xpath in Python. As shown in code below, I want to find the html content of the each of product nodes. Does it have any methods like product.html?
我试图在 Python 中使用 lxml 和 xpath 获取子节点的 HTML 内容。如下代码所示，我想找到每个产品节点的 html 内容。它有类似product.html 的方法吗？
productGrids = tree.xpath("//div[@class='name']/parent::*")
for product in productGrids:
print #html content of product
采纳答案by Walty Yeung
from lxml import etree
print(etree.tostring(root, pretty_print=True))
you may see more examples here: http://lxml.de/tutorial.html
您可能会在这里看到更多示例：http: //lxml.de/tutorial.html
回答by vezult
I believe you want to use the tostring()method:
我相信你想使用这个tostring()方法：
from lxml import etree
tree = etree.fromstring('<html><head><title>foo</title></head><body><div class="name"><p>foo</p></div><div class="name"><ul><li>bar</li></ul></div></body></html>')
for elem in tree.xpath("//div[@class='name']"):
# pretty_print ensures that it is nicely formatted.
print etree.tostring(elem, pretty_print=True)
回答by Saurabh Chandra Patel
another way to do this
另一种方法来做到这一点
x=doc.xpath("//div[@class='name']/parent::*")
print(map(etree.tostring,x))
回答by randompast
After right clicking (copy, copy xpath) on the specific field you want (in chrome's inspector), you might get something like this:
在您想要的特定字段（在 chrome 的检查器中）上右键单击（复制、复制 xpath）后，您可能会得到如下内容：
//*[@id="specialID"]/div[12]/div[2]/h4/text()[1]
If you wanted that text element for each "specialID"
如果您想要每个“specialID”的文本元素
//*[@id="specialID"]/div/div[2]/h4/text()[1]
You could select another field and it'll interleave the results
您可以选择另一个字段，它会交错结果
//*[@id="specialID"]/div/div[2]/h4/text()[1] | //*[@id="specialID"]/div/some/weird/path[95]
Example could be improved, but it illustrates the point:
示例可以改进，但它说明了这一点：
//*[@id="mw-content-text"]/div/ul[1]/li[11]/text()
from lxml import html
import requests
page = requests.get('https://en.wikipedia.org/wiki/Web_scraping')
tree = html.fromstring(page.content)
data = tree.xpath('//*[@id="mw-content-text"]/div/ul[1]/li/a/text() | //*[@id="mw-content-text"]/div/ul[1]/li/text()[1]')
print(len(data))
for i in range(len(data)):
print(data[i])
回答by Virako
You can use product.text_content()
您可以使用 product.text_content()
回答by Sivashanmugam Kannan
Simple function to get innerHTML or innerXML
.
Try it out directly https://pyfiddle.io/fiddle/631aa049-2785-4c58-bf82-eff4e2f8bedb/
.
获取innerHTML 或 innerXML 的简单函数
。
直接尝试https://pyfiddle.io/fiddle/631aa049-2785-4c58-bf82-eff4e2f8bedb/
。
function
功能
def innerXML(elem):
elemName = elem.xpath('name(/*)')
resultStr = ''
for e in elem.xpath('/'+ elemName + '/node()'):
if(isinstance(e, str) ):
resultStr = resultStr + ''
else:
resultStr = resultStr + etree.tostring(e, encoding='unicode')
return resultStr
invocation
调用
XMLElem = etree.fromstring("<div>I am<name>Jhon <last.name> Corner</last.name></name>.I work as <job>software engineer</job><end meta='bio' />.</div>")
print(innerXML(XMLElem))
.
Logic Behind
.
背后的逻辑
- get the outermost element name first,
- Then get all the child nodes
- Convert all the child nodes to string using
tostring - Concatinate Them
- 首先获取最外面的元素名称，
- 然后获取所有子节点
- 使用将所有子节点转换为字符串
tostring - 连接它们
