java “HH:MM:SS”中的秒数
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Number of seconds in "HH:MM:SS"
提问by Bogdan Balan
What's the best way to get the number of seconds in a string representation like "hh:mm:ss"?
在像“hh:mm:ss”这样的字符串表示中获取秒数的最佳方法是什么？
Obviously Integer.parseInt(s.substring(...)) * 3600 + Integer.parseInt(s.substring(...)) * 60 + Integer.parseInt(s.substring(...)) works.
显然 Integer.parseInt(s.substring(...)) * 3600 + Integer.parseInt(s.substring(...)) * 60 + Integer.parseInt(s.substring(...)) 有效。
But I don't want to test that, and reinvent the wheal, I expect there is a way to use DateTimeFormat or other classes from standard libraries.
但我不想测试它，并重新发明风团，我希望有一种方法可以使用 DateTimeFormat 或标准库中的其他类。
Thanks!
谢谢！
回答by user85421
DateFormat dateFormat = new SimpleDateFormat("HH:mm:ss");
Date reference = dateFormat.parse("00:00:00");
Date date = dateFormat.parse(string);
long seconds = (date.getTime() - reference.getTime()) / 1000L;
referenceis used to compensate for different timezones and there is no problem with daylight saving time because SimpleDateFormat does NOT use the actual date, it return the Epoc date (January 1st, 1970 = no DST).
reference用于补偿不同的时区，夏令时没有问题，因为 SimpleDateFormat 不使用实际日期，它返回 Epoc 日期（1970 年 1 月 1 日 = 无 DST）。
Simplifying (not much):
简化（不多）：
DateFormat dateFormat = new SimpleDateFormat("HH:mm:ss");
dateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
Date date = dateFormat.parse("01:00:10");
long seconds = date.getTime() / 1000L;
but I would still have a look at Joda-Time...
但我还是会看看 Joda-Time ......
回答by pakore
An original way:
The Calendarversion (updated with the suggestions in the comments):
原始方式：Calendar版本（根据评论中的建议更新）：
DateFormat dateFormat = new SimpleDateFormat("HH:mm:ss");
dateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
Date date = dateFormat.parse(string);
//Here you can do manually date.getHours()*3600+date.getMinutes*60+date.getSeconds();
//It's deprecated to use Date class though.
//Here it goes an original way to do it.
Calendar time = new GregorianCalendar();
time.setTime(date);
time.setTimeZone(TimeZone.getTimeZone("UTC"));
time.set(Calendar.YEAR,1970); //Epoc year
time.set(Calendar.MONTH,Calendar.JANUARY); //Epoc month
time.set(Calendar.DAY_OF_MONTH,1); //Epoc day of month
long seconds = time.getTimeInMillis()/1000L;
Disclaimer: I've done it by heart, just looking at the documentation, so maybe there is a typo or two.
免责声明：我已经用心完成了，只是看了一下文档，所以可能有一两个错字。
回答by Aravind Yarram
joda-time is 1 options. infact i prefer that library for all date manipulations. I was going thru the java 5 javadoc and found this enum class which is simple and useful for you. java.util.concurrent.TimeUnit. look at the convert(...) methods. http://download.oracle.com/docs/cd/E17476_01/javase/1.5.0/docs/api/java/util/concurrent/TimeUnit.html
joda-time 是 1 个选项。事实上，我更喜欢该库进行所有日期操作。我正在浏览 java 5 javadoc，发现这个 enum 类对您来说既简单又有用。java.util.concurrent.TimeUnit。看看 convert(...) 方法。http://download.oracle.com/docs/cd/E17476_01/javase/1.5.0/docs/api/java/util/concurrent/TimeUnit.html
回答by Peter Hanneman
Here is the link to a Java example of time formatting.
这是时间格式的 Java 示例的链接。
http://download.oracle.com/docs/cd/E17409_01/javase/tutorial/i18n/format/simpleDateFormat.html
http://download.oracle.com/docs/cd/E17409_01/javase/tutorial/i18n/format/simpleDateFormat.html
