在 PHP 中将对象作为参数传递

Pass an object as parameter in PHP

提问by Hoan Dang

In Java, I can pass an object straight in parameter

在 Java 中，我可以直接在参数中传递一个对象

public int foo (Bar bar)
{
    ... call the methods from Bar class
}

So how can I do same thing with PHP. Thanks This is my code:

那么我如何用 PHP 做同样的事情。谢谢 这是我的代码：

class Photo
{
    private $id, $name, $description;
    public function Photo($id, $name, $description)
    {
        $this->id = $id;
        $this->name = $name;
        $this->description = $description;
    }
}
class Photos
{
    private $id = 0;
    private $photos = array();

    private function add(Photo $photo)
    {
        array_push($this->photos, $photo);
    }
    public function addPhoto($name, $description)
    {
        add(new Photo(++$this->id, $name, $description));
    }
}
$photos = new Photos();
$photos->addPhoto('a', 'fsdfasd');
var_dump($photos); // blank

If I change the function add

如果我改变功能添加

function add($name, $description)
{
    array_push($this->photos, new Photo(++$this->id, $name, $description));
}

It works pefectly. So What is wrong ?

它完美地工作。那么有什么问题呢？

回答by Tim Cooper

You do it the exact same way, just with some syntax changes, of course:

当然，您以完全相同的方式执行此操作，只是进行了一些语法更改：

public function foo(Bar $bar)
{
    // $bar->method()
}

Keep in mind that you can only type hintfor classes and arrays.

请记住，您只能为类和数组键入提示。