Java 在特定索引之后从列表中删除所有元素
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Remove all elements from a List after a particular index
提问by Abhi
Is there any convenient way in List/ArrayList by which we can remove all elements of a List after a particular index. Instead of manually looping through it for removing.
在 List/ArrayList 中是否有任何方便的方法可以在特定索引之后删除 List 的所有元素。而不是手动循环遍历它以进行删除。
To be more explanatory, if I have a list of 10 elements, I want to mention index 3 and then all elements after index 3 gets removed and my list would consist of only starting 4 elements now (counts from 0)
更详细地说，如果我有一个包含 10 个元素的列表，我想提到索引 3，然后索引 3 之后的所有元素都被删除，我的列表现在只包含 4 个元素（从 0 开始计数）
采纳答案by user2357112 supports Monica
list.subList(4, list.size()).clear();
Sublist operations are reflected in the original list, so this clears everything from index 4 inclusive to list.size()exclusive, a.k.a. everything after index 3. Range removal is specifically used as an example in the documentation:
子列表操作反映在原始列表中，因此这会清除从索引 4 到list.size()独占的所有内容，也就是索引 3 之后的所有内容。文档中专门使用范围删除作为示例：
This method eliminates the need for explicit range operations (of the sort that commonly exist for arrays). Any operation that expects a list can be used as a range operation by passing a subList view instead of a whole list. For example, the following idiom removes a range of elements from a list:
list.subList(from, to).clear();
此方法消除了对显式范围操作（数组通常存在的排序）的需要。通过传递子列表视图而不是整个列表，任何需要列表的操作都可以用作范围操作。例如，以下习语从列表中删除一系列元素：
list.subList(from, to).clear();
回答by AJJ
Using sublist() and clear(),
使用 sublist() 和 clear()，
public class Count
{
public static void main(String[] args)
{
ArrayList<String> arrayList = new ArrayList<String>();
arrayList.add("1");
arrayList.add("2");
arrayList.add("3");
arrayList.add("4");
arrayList.add("5");
arrayList.subList(2, arrayList.size()).clear();
System.out.println(arrayList.size());
}
}
