Javascript 在 ES6 模块中导出多个类
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Export multiple classes in ES6 modules
提问by ambient
I'm trying to create a module that exports multiple ES6 classes. Let's say I have the following directory structure:
我正在尝试创建一个导出多个 ES6 类的模块。假设我有以下目录结构:
my/
└── module/
├── Foo.js
├── Bar.js
└── index.js
Foo.js
and Bar.js
each export a default ES6 class:
Foo.js
并且Bar.js
每个都导出一个默认的 ES6 类:
// Foo.js
export default class Foo {
// class definition
}
// Bar.js
export default class Bar {
// class definition
}
I currently have my index.js
set up like this:
我目前的index.js
设置是这样的:
import Foo from './Foo';
import Bar from './Bar';
export default {
Foo,
Bar,
}
However, I am unable to import. I want to be able to do this, but the classes aren't found:
但是,我无法导入。我希望能够做到这一点,但找不到类:
import {Foo, Bar} from 'my/module';
What is the correct way to export multiple classes in an ES6 module?
在 ES6 模块中导出多个类的正确方法是什么?
回答by webdeb
Try this in your code:
在你的代码中试试这个:
import Foo from './Foo';
import Bar from './Bar';
// without default
export {
Foo,
Bar,
}
Btw, you can also do it this way:
顺便说一句,你也可以这样做:
// bundle.js
export { default as Foo } from './Foo'
export { default as Bar } from './Bar'
export { default } from './Baz'
// and import somewhere..
import Baz, { Foo, Bar } from './bundle'
Using export
使用 export
export const MyFunction = () => {}
export const MyFunction2 = () => {}
const Var = 1;
const Var2 = 2;
export {
Var,
Var2,
}
// Then import it this way
import {
MyFunction,
MyFunction2,
Var,
Var2,
} from './foo-bar-baz';
The difference with export default
is that you can export something, and apply the name where you import it:
与 的区别export default
在于您可以导出某些内容,并在导入时应用名称:
// export default
export default class UserClass {
constructor() {}
};
// import it
import User from './user'
回答by Syed
Hope this helps:
希望这可以帮助:
// Export (file name: my-functions.js)
export const MyFunction1 = () => {}
export const MyFunction2 = () => {}
export const MyFunction3 = () => {}
// if using `eslint` (airbnb) then you will see warning, so do this:
const MyFunction1 = () => {}
const MyFunction2 = () => {}
const MyFunction3 = () => {}
export {MyFunction1, MyFunction2, MyFunction3};
// Import
import * as myFns from "./my-functions";
myFns.MyFunction1();
myFns.MyFunction2();
myFns.MyFunction3();
// OR Import it as Destructured
import { MyFunction1, MyFunction2, MyFunction3 } from "./my-functions";
// AND you can use it like below with brackets (Parentheses) if it's a function
// AND without brackets if it's not function (eg. variables, Objects or Arrays)
MyFunction1();
MyFunction2();
回答by inostia
@webdeb's answer didn't work for me, I hit an unexpected token
error when compiling ES6 with Babel, doing named default exports.
@webdeb 的回答对我不起作用,我unexpected token
在使用 Babel 编译 ES6 时遇到错误,执行命名的默认导出。
This worked for me, however:
然而,这对我有用:
// Foo.js
export default Foo
...
// bundle.js
export { default as Foo } from './Foo'
export { default as Bar } from './Bar'
...
// and import somewhere..
import { Foo, Bar } from './bundle'
回答by PaoPao
// export in index.js
export { default as Foo } from './Foo';
export { default as Bar } from './Bar';
// then import both
import { Foo, Bar } from 'my/module';
回答by Schmidko
For exporting the instances of the classes you can use this syntax:
要导出类的实例,您可以使用以下语法:
// export index.js
const Foo = require('./my/module/foo');
const Bar = require('./my/module/bar');
module.exports = {
Foo : new Foo(),
Bar : new Bar()
};
// import and run method
const {Foo,Bar} = require('module_name');
Foo.test();