Java 无法解析构造函数（Android Intent）
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Cannot resolve constructor (Android Intent)
提问by User
I'm trying to create a simple button that opens to a different activity:
我正在尝试创建一个打开不同活动的简单按钮：
package com.example.xxx.buttonexample;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.widget.Button;
import android.view.View;
import android.view.View.OnClickListener;
public class MainActivity extends Activity {
Button button;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
btnClick();
}
public void btnClick() {
button = (Button) findViewById(R.id.button1);
button.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v)
{
Intent intent = new Intent(this,emergencyIntent.class);
startActivity(intent);
}
});
}
}
Here is my emergencyIntent.class file:
这是我的 EmergencyIntent.class 文件：
package com.example.xxx.buttonexample;
import android.app.Activity;
import android.os.Bundle;
public class emergencyIntent extends Activity
{
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
// The activity is being created.
}
}
I received a error:
我收到一个错误：
"Cannot resolve constructor 'intent(anonymous android.view.View.OnClickListener, java.lang.Class(com.example.xxx.buttonexample.emergencyIntent))'.
“无法解析构造函数'intent（匿名android.view.View.OnClickListener，java.lang.Class（com.example.xxx.buttonexample.emergencyIntent））'。
采纳答案by Krupal Shah
Just replace thisin first parameter with MainActivity.this. like:
只需将this第一个参数替换为MainActivity.this. 喜欢：
Intent intent = new Intent(MainActivity.this,emergencyIntent.class);
The error is because you are writing it in public void onClick(View v), where 'this' will mean instance of anonymous class that implements View.OnClickListener. while first parameter in Intent constructor Intent(Context context, Class<?> cls)requires Activity context.
错误是因为您正在编写它public void onClick(View v)，其中 ' this' 将表示实现View.OnClickListener. 而 Intent 构造函数中的第一个参数Intent(Context context, Class<?> cls)需要 Activity 上下文。
回答by Yogesh Borhade
package com.example.xxx.buttonexample;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.widget.Button;
import android.view.View;
import android.view.View.OnClickListener;
public class MainActivity extends Activity {
Button button;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
button = (Button) findViewById(R.id.button1);
button.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v)
{
Intent intent = new Intent(MainActivity.this,emergencyIntent.class);
startActivity(intent);
//Or Intent intent = new Intent(getApplicationContext(),emergencyIntent.class);
}
});
}
}
回答by user6741985
package com.example.xxx.buttonexample;
包 com.example.xxx.buttonexample;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.widget.Button;
import android.view.View;
import android.view.View.OnClickListener;
public class MainActivity extends Activity {
Button button;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
button = (Button) findViewById(R.id.button1);
button.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v)
{
Intent intent = new Intent(MainActivity.this,emergencyIntent.class);
startActivity(intent); //Or Intent intent = new Intent(getApplicationContext(),emergencyIntent.class);
开始活动（意图）；//或 Intent intent = new Intent(getApplicationContext(),emergencyIntent.class);
}
});## Heading ##
});##标题##
