验证电话号码 ios
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Validate phone number ios
提问by Thomas Clayson
I need to validate an international phone number.
我需要验证一个国际电话号码。
I know its difficult to validate an international phone number, so I'm going to keep it simple:
我知道验证国际电话号码很困难，所以我将保持简单：
+or 00 then 6-14 numbers
+或 00 然后是 6-14 个数字
My current code using a regex isn't working for some reason which I can't work out. It just says that it cannot open the regex and crashes.
由于某种我无法解决的原因，我当前使用正则表达式的代码不起作用。它只是说它无法打开正则表达式并崩溃。
Here is my current code:
这是我当前的代码：
NSString *phoneRegex = @"^[\+(00)][0-9]{6,14}$";
NSPredicate *phoneTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", phoneRegex];
BOOL phoneValidates = [phoneTest evaluateWithObject:phoneNumber];
Where am I going wrong?
我哪里错了？
Thanks!
谢谢！
回答by whiteagle
NSString *phoneRegex = @"^((\+)|(00))[0-9]{6,14}$";
This way is bit better. Your code will work as well if you escape the "\".
这种方式好一些。如果您转义“\”，您的代码也能正常工作。
回答by Manuel Escrig
Copy & Pastemethod to validate phone numbers:
复制和粘贴方法来验证电话号码：
- (BOOL)validatePhone:(NSString *)phoneNumber
{
NSString *phoneRegex = @"^((\+)|(00))[0-9]{6,14}$";
NSPredicate *phoneTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", phoneRegex];
return [phoneTest evaluateWithObject:phoneNumber];
}
or Open sourceLibrary for validating Phone Numbers
或用于验证电话号码的开源库
回答by jainvikram444
well it depends on how strict you want to be it doesn't seem like this regex is especially strict. this regex says:
好吧，这取决于您想要的严格程度，这个正则表达式似乎并不特别严格。这个正则表达式说：
start at beginning of line match one + (or maybe 1 or 0) which seems ambiguous (but may not be depending on implementation) because the capture parentheses:() breaks up the relationship of the + and the ? possibly misplaced : match any digit 0-9 1 or 0 times 6-14 times then one digit 0-9 then end of line. also you note that any backslash will have to be doubled... @"\b" for a word boundary. you may want to try something like...
从行首开始匹配一个 +（或者可能是 1 或 0），这看起来不明确（但可能不取决于实现），因为捕获括号:() 打破了 + 和 ? 可能错位：匹配任何数字 0-9 1 或 0 次 6-14 次，然后匹配一位数字 0-9 然后行尾。您还注意到，任何反斜杠都必须加倍...... @"\b" 用于单词边界。你可能想尝试类似...
@"\b[\d]{3}\-[\d]{3}\-[\d]{4}\b"
would I think match your example, but it wouldn't match
(555) 555 - 5555 or
555.555.5555 or
+44 1865 55555
回答by mandeep
txtlpmobile.text is the string(Mobile no ur gonna enter)
txtlpmobile.text 是字符串（手机没有你要输入）
int length = [self getLength:txtLpMobile.text];
if(length == 10) {
if(range.length == 0)
return NO;
}
if(length == 3){
NSString *num = [self formatNumber:txtLpMobile.text];
txtLpMobile.text = [NSString stringWithFormat:@"(%@) ",num];
if(range.length > 0) {
txtLpMobile.text = [NSString stringWithFormat:@"%@",[num substringToIndex:3]];
}
} else if(length == 6) {
NSString *num = [self formatNumber:txtLpMobile.text];
txtLpMobile.text = [NSString stringWithFormat:@"(%@) %@-",[num substringToIndex:3],[num substringFromIndex:3]];
if(range.length > 0) {
txtLpMobile.text = [NSString stringWithFormat:@"(%@) %@",[num substringToIndex:3],[num substringFromIndex:3]];
}
}
NSUInteger newLength;
newLength = [txtLpMobile.text length] + [string length] - range.length;
NSCharacterSet *cs = [[NSCharacterSet characterSetWithCharactersInString:NUMBERS_ONLY] invertedSet];
NSString *filtered = [[string componentsSeparatedByCharactersInSet:cs] componentsJoinedByString:@""];
return (([string isEqualToString:filtered])&&(newLength <= CHARACTER_LIMIT));
for formatting number
用于格式化数字
-(NSString*)formatNumber:(NSString*)mobileNumber
{
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];
int length = [mobileNumber length];
if(length > 10)
{
mobileNumber = [mobileNumber substringFromIndex: length-10];
}
return mobileNumber;
}
for getting length
为了得到长度
-(int)getLength:(NSString*)mobileNumber
{
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
mobileNumber = [mobileNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];
int length = [mobileNumber length];
return length;
}
回答by NSurajit
NSString *phoneRegex = @"^((\\+)|(00))[0-9]{6,14}|[0-9]{6,14}$";
NSString *phoneRegex = @"^((\\+)|(00))[0-9]{6,14}|[0-9]{6,14}$";
This is tested RegularExpression This will accept with country code OR without country code
这是经过测试的 RegularExpression 这将接受国家代码或不接受国家代码
回答by meaning-matters
The only good way to validate phone numbers is to use Google's amazing LibPhoneNumber. There's an iOS port, or you can run the JavaScript implementation in a hidden UIWebView.
验证电话号码的唯一好方法是使用Google 惊人的 LibPhoneNumber。有一个 iOS 端口，或者您可以在隐藏的UIWebView.
(I've done the latter years ago when their was no iOS port yet. Works like a charm and is very fast even on old iPhones.)
（我在几年前完成了后者，当时他们还没有 iOS 端口。工作就像一个魅力，即使在旧 iPhone 上也非常快。）
回答by User558
Easy way to validate phone number and password limit , just follow the below process.
验证电话号码和密码限制的简单方法，只需按照以下过程操作即可。
if ((self.mobileTxtFld.text.length < 10 )) {
[_mobileTxtFld becomeFirstResponder];
}
else if ((self.passwordTxtFld.text.length < kPasswordCharacterMinLimit) || (self.passwordTxtFld.text.length > kPasswordCharacterMaxLimit)) {
// show alert
}
after that you can implement textfiled delegate method "shouldChangeCharactersInRange" in that just write this code
之后，您可以实现文本文件委托方法“shouldChangeCharactersInRange”，只需编写此代码
if (textField == _mobileTxtFld) {
if([string rangeOfCharacterFromSet:ALLOWED_NUMBERS].location == NSNotFound){
NSUInteger newLength = [textField.text length] + [string length] - range.length;
if(newLength > kMobileNumberLimit - 1){
if(textField.text.length != kMobileNumberLimit){
textField.text = [NSString stringWithFormat:@"%@%@",textField.text,string];
}
[textField resignFirstResponder];
return NO;
}
else{
return YES;
}
}
else{
return NO;
}
}
return YES;
here ALLOWED_NUMBERS and kMobileNumberLimit are
这里 ALLOWED_NUMBERS 和 kMobileNumberLimit 是
#define kMobileNumberLimit 10
#define ALLOWED_NUMBERS [[NSCharacterSet decimalDigitCharacterSet] invertedSet]
#define minLimit 6
#define maxLimit 17
回答by Abhishek Mishra
In swift 4 -
在 swift 4 -
func ValidateMobileNumber(txtFeid : UITextField, strChk : String, range: NSRange) -> Bool {
if txtFeid.text!.count >= 10 {
return false
}
let formatePre = "^((\+)|(00))[0-9]{6,14}$"
let resultPredicate : NSPredicate = NSPredicate(format: "SELF MATCHES %@",formatePre)
return resultPredicate.evaluate(with: strChk)
}
回答by HIMANSHU VARSHNEY
-(int)findLength:(NSString*)phoneNumber
{
phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];
int length = [phoneNumber length];
return length;
}
}
