javascript this.src.replace img src 用于多张图片
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this.src.replace img src for multiple images
提问by Troublesum
I want to change the source of an image when hovering over it.
我想在将鼠标悬停在图像上时更改图像的来源。
I've managed to do it for one image, by
我已经成功地为一张图片做到了
<img id="image1" src="image1-grey.png" onmouseover=colorImage(this) />"
And:
和：
function colorImage(x){
document.getElementById("image1").src = x.src.replace("grey", "color");
}
I have a dozen or so images - all in two versions, grey and color.
我有十几个图像 - 都有两个版本，灰色和彩色。
Now I guess I could repeat the function above for all the images individually, but there must be a cleaner way.
现在我想我可以单独为所有图像重复上述功能，但必须有一种更简洁的方法。
This is what I figured, but it doesn't work:
这是我的想法，但它不起作用：
<img id="image1" src="image1-grey.png" onmouseover=colorImage(image1) />"
And:
和：
function colorImage(x){
document.getElementById(x).src = this.src.replace("grey", "color");
}
This way, I thought, I'd only have one function for all the images. But no. Why not?
这样，我想，我对所有图像只有一个功能。但不是。为什么不？
Thanks a lot in advance!
非常感谢！
回答by sachleen
Since you're passing a reference to the image as a parameter, you don't need to use document.getElementById... you already have it!
由于您将图像的引用作为参数传递，因此您不需要使用 document.getElementById ……您已经拥有了！
function colorImage(x){
x.src = x.src.replace("grey", "color");
}
You can continue to call the function using your first way:
您可以继续使用第一种方式调用该函数：
<img id="image1" src="image1-grey.png" onmouseover=colorImage(this) />
回答by Troublesum
Looks like your problem is with image1in the line below
看起来您的问题出image1在下面的行中
onmouseover=colorImage(image1)
it needs to be in quotes like you are passing a string (shown below)
它需要像你传递一个字符串一样用引号引起来（如下所示）
onmouseover=colorImage('image1')
The way your passing it now you are sending a javascript variable named image1(which would be undefined) instead of the string name you want "image1"
您现在传递它的方式是发送一个名为image1（将是undefined）的 javascript 变量而不是您想要的字符串名称"image1"
