pandas 将熊猫浮点系列转换为 int
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convert pandas float series to int
提问by Christopher
I am discretizing my series for a learner. I really need the series to be in float, and I reallyneed to avoid for loops.
我正在为学习者离散化我的系列。我真的需要这个系列是浮动的，我真的需要避免 for 循环。
How do I convert this series from float to int?
如何将这个系列从 float 转换为 int？
Here is my function that is currently failing:
这是我目前失败的功能：
def discretize_series(s,count,normalized=True):
def discretize(value,bucket_size):
return value % bucket_size
if normalized:
maximum = 1.0
else:
minimum = np.min(s)
s = s[:] - minimum
maximum = np.max(s)
bucket_size = maximum / float(count)
Here is the line that causes the function to fail:
这是导致函数失败的行：
s = int((s[:] - s[:] % bucket_size)/bucket_size)
The int() induces a casting error: I am unable to cast the pandas series as an int series.
int() 会导致转换错误：我无法将 pandas 系列转换为 int 系列。
return s
If I remove the int(), the function works, so I may just see if I can get it to work anyway.
如果我删除 int()，该函数就可以工作，所以我可能只是看看我是否可以让它工作。
回答by Andras Deak
The regular python intfunction only works for scalars. You should either use a numpy function to round the data, either
常规 pythonint函数仅适用于标量。您应该使用 numpy 函数来舍入数据，或者
s = np.round((s - s % bucket_size) / bucket_size) #to round properly; or
s = np.fix((s - s % bucket_size) / bucket_size) #to round towards 0
and if you actually want to convert to an integer type, use
如果您确实想转换为整数类型，请使用
s = s.astype(int)
to cast your array.
投射你的数组。
