Python Pygame 中的倒数计时器

Countdown timer in Pygame

提问by adamo94

I started using pygame and I want to do simple game. One of the elements which I need is countdown timer. How can I do the countdown time (eg 10 seconds) in PyGame?

我开始使用 pygame 并且我想做简单的游戏。我需要的元素之一是倒数计时器。如何在 PyGame 中进行倒计时（例如 10 秒）？

采纳答案by DanteVoronoi

On this page you will find what you are looking for http://www.pygame.org/docs/ref/time.html#pygame.time.get_ticks
You download ticks once before beginning the countdown (which can be a trigger in the game - the key event, whatever). For example:

在此页面上，您将找到您要查找的内容http://www.pygame.org/docs/ref/time.html#pygame.time.get_ticks
您在开始倒计时之前下载一次刻度（这可以是游戏 - 关键事件，无论如何）。例如：

start_ticks=pygame.time.get_ticks() #starter tick
while mainloop: # mainloop
    seconds=(pygame.time.get_ticks()-start_ticks)/1000 #calculate how many seconds
    if seconds>10: # if more than 10 seconds close the game
        break
    print (seconds) #print how many seconds

回答by John

There are several ways you can do this- here's one. Python doesn't have a mechanism for interrupts as far as I know.

有几种方法可以做到这一点 - 这是一种。据我所知，Python 没有中断机制。

import time, datetime

timer_stop = datetime.datetime.utcnow() +datetime.timedelta(seconds=10)
while True:
    if datetime.datetime.utcnow() > timer_stop:
        print "timer complete"
        break

回答by sloth

Another easy way is to simply use pygame's event system.

另一种简单的方法是简单地使用 pygame 的事件系统。

Here's a simple example:

这是一个简单的例子：

import pygame
pygame.init()
screen = pygame.display.set_mode((128, 128))
clock = pygame.time.Clock()

counter, text = 10, '10'.rjust(3)
pygame.time.set_timer(pygame.USEREVENT, 1000)
font = pygame.font.SysFont('Consolas', 30)

while True:
    for e in pygame.event.get():
        if e.type == pygame.USEREVENT: 
            counter -= 1
            text = str(counter).rjust(3) if counter > 0 else 'boom!'
        if e.type == pygame.QUIT: break
    else:
        screen.fill((255, 255, 255))
        screen.blit(font.render(text, True, (0, 0, 0)), (32, 48))
        pygame.display.flip()
        clock.tick(60)
        continue
    break

回答by Douglas - 15 year old Pythoner

This is actually quite simple. Thank Pygame for creating a simple library!

这其实很简单。感谢 Pygame 创建了一个简单的库！

import pygame
x=0
while x < 10:
    x+=1
    pygame.time.delay(1000)

That's all there is to it! Have fun with pygame!

这里的所有都是它的！玩得开心 pygame！

回答by skrx

pygame.time.Clock.tickreturns the time in milliseconds since the last clock.tickcall (delta time, dt), so you can use it to increase or decrease a timer variable.

pygame.time.Clock.tick返回自上次clock.tick调用（delta time, dt）以来的时间（以毫秒为单位），因此您可以使用它来增加或减少计时器变量。

import pygame as pg


def main():
    pg.init()
    screen = pg.display.set_mode((640, 480))
    font = pg.font.Font(None, 40)
    gray = pg.Color('gray19')
    blue = pg.Color('dodgerblue')
    # The clock is used to limit the frame rate
    # and returns the time since last tick.
    clock = pg.time.Clock()
    timer = 10  # Decrease this to count down.
    dt = 0  # Delta time (time since last tick).

    done = False
    while not done:
        for event in pg.event.get():
            if event.type == pg.QUIT:
                done = True

        timer -= dt
        if timer <= 0:
            timer = 10  # Reset it to 10 or do something else.

        screen.fill(gray)
        txt = font.render(str(round(timer, 2)), True, blue)
        screen.blit(txt, (70, 70))
        pg.display.flip()
        dt = clock.tick(30) / 1000  # / 1000 to convert to seconds.


if __name__ == '__main__':
    main()
    pg.quit()

回答by Anshuman Bharadwaj

There are many ways to do this and it is one of them

有很多方法可以做到这一点，它是其中之一

import pygame,time, sys
from pygame.locals import*
pygame.init()
screen_size = (400,400)
screen = pygame.display.set_mode(screen_size)
pygame.display.set_caption("timer")
time_left = 90 #duration of the timer in seconds
crashed  = False
font = pygame.font.SysFont("Somic Sans MS", 30)
color = (255, 255, 255)

while not crashed:
    for event in pygame.event.get():
        if event.type == QUIT:
            crashed = True
    total_mins = time_left//60 # minutes left
    total_sec = time_left-(60*(total_mins)) #seconds left
    time_left -= 1
    if time_left > -1:
        text = font.render(("Time left: "+str(total_mins)+":"+str(total_sec)), True, color)
        screen.blit(text, (200, 200))
        pygame.display.flip()
        screen.fill((20,20,20))
        time.sleep(1)#making the time interval of the loop 1sec
    else:
        text = font.render("Time Over!!", True, color)
        screen.blit(text, (200, 200))
        pygame.display.flip()
        screen.fill((20,20,20))




pygame.quit()
sys.exit()