ios 在 swift 3 中使用对象执行选择器
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Perform Selector With Object in swift 3
提问by Zaheer Abbas
I am trying to perform selector with object in swift 3.0
我正在尝试在swift 3.0 中使用对象执行选择器
I have a selector which have one parameter
我有一个选择器，它有一个参数
func imageSelected(aImage : UIImage)
func imageSelected(aImage : UIImage)
and I am calling it like
我这样称呼它
viewC.perform(Selector.init("imageSelected:"), with: image, afterDelay: 0.1)
viewC.perform(Selector.init("imageSelected:"), with: image, afterDelay: 0.1)
But the app crashes with error that the selector is not defined.
但是应用程序因未定义选择器的错误而崩溃。
采纳答案by Zaheer Abbas
It started working well as, I modified the selector being called
它开始运行良好，因为我修改了被调用的选择器
from
从
func imageSelected(aImage : UIImage)
to this
对此
func imageSelected(_ aImage : UIImage)
回答by Sweeper
Here's something I always do when I encounter selectors in swift: Ignore the parameters, just use the name.
当我在 swift 中遇到选择器时，我总是这样做：忽略参数，只使用名称。
You used this:
你用过这个：
imageSelected:
What is that :doing there? Delete it! Just use the name of the method!
那:在那里做什么？删除它！只需使用方法的名称！
Also, there is this great #selectorsyntactic sugar, please use that:
此外，还有这个很棒的#selector语法糖，请使用：
viewC.perform(#selector(imageSelected), with: image, afterDelay: 0.1)
回答by sonali
This is for swift 4.0
这是为了 swift 4.0
perform(#selector(yourMethodHere), with: nil, afterDelay: 1)
Add @objc flag before your function
在函数前添加 @objc 标志
@objc public func yourMethodHere(){
//your code here
}
