jQuery Uncaught TypeError:无法读取未定义的属性“fn”(匿名函数)

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时间:2020-08-26 09:48:02  来源:igfitidea点击:

jQuery Uncaught TypeError: Cannot read property 'fn' of undefined (anonymous function)

jquery

提问by user1048676

All, I'm getting an error from some of my code that I downloaded. Here is the code:

所有,我从我下载的一些代码中得到一个错误。这是代码:

/*----------------------------------------------------------------------*/
/* wl_Alert v 1.1 
/* description: Handles alert boxes
/* dependency: jquery UI Slider, fadeOutSlide plugin
/*----------------------------------------------------------------------*/


$.fn.wl_Alert = function (method) {
var args = arguments;
return this.each(function () {

    var $this = $(this);


    if ($.fn.wl_Alert.methods[method]) {
        return $.fn.wl_Alert.methods[method].apply(this, Array.prototype.slice.call(args, 1));
    } else if (typeof method === 'object' || !method) {
        if ($this.data('wl_Alert')) {
            var opts = $.extend({}, $this.data('wl_Alert'), method);
        } else {

            var opts = $.extend({}, $.fn.wl_Alert.defaults, method, $this.data());
        }
    } else {
        $.error('Method "' + method + '" does not exist');
    }


    if (!$this.data('wl_Alert')) {

        $this.data('wl_Alert', {});

        //bind click events to hide alert box
        $this.bind('click.wl_Alert', function (event) {
            event.preventDefault();

            //Don't hide if it is sticky
            if (!$this.data('wl_Alert').sticky) {
                $.fn.wl_Alert.methods.close.call($this[0]);
            }

            //prevent hiding the box if an inline link is clicked
        }).find('a').bind('click.wl_Alert', function (event) {
            event.stopPropagation();
        });
    } else {

    }
    //show it if it is hidden
    if ($this.is(':hidden')) {
        $this.slideDown(opts.speed / 2);
    }

    if (opts) $.extend($this.data('wl_Alert'), opts);
});

};

$.fn.wl_Alert.defaults = {
speed: 500,
sticky: false,
onBeforeClose: function (element) {},
onClose: function (element) {}
};
$.fn.wl_Alert.version = '1.1';


$.fn.wl_Alert.methods = {
close: function () {
    var $this = $(this),
        opts = $this.data('wl_Alert');
    //call callback and stop if it returns false
    if (opts.onBeforeClose.call(this, $this) === false) {
        return false;
    };
    //fadeout and call an callback
    $this.fadeOutSlide(opts.speed, function () {
        opts.onClose.call($this[0], $this);
    });
},
set: function () {
    var $this = $(this),
        options = {};
    if (typeof arguments[0] === 'object') {
        options = arguments[0];
    } else if (arguments[0] && arguments[1] !== undefined) {
        options[arguments[0]] = arguments[1];
    }
    $.each(options, function (key, value) {
        if ($.fn.wl_Alert.defaults[key] !== undefined || $.fn.wl_Alert.defaults[key] == null) {
            $this.data('wl_Alert')[key] = value;
        } else {
            $.error('Key "' + key + '" is not defined');
        }
    });

}
};

//to create an alert box on the fly
$.wl_Alert = function (text, cssclass, insert, after, options) {
//go thru all
$('div.alert').each(function () {
    var _this = $(this);
    //...and hide if one with the same text is allready set
    if (_this.text() == text) {
        _this.slideUp($.fn.wl_Alert.defaults.speed);
    }
});

//create a new DOM element and inject it
var al = $('<div class="alert ' + cssclass + '">' + text + '</div>').hide();
(after) ? al.appendTo(insert).wl_Alert(options) : al.prependTo(insert).wl_Alert(options);

//return the element
return al;
};

Has anyone seen this type of error before? How would I resolve something like this? Thanks for any advice you have!

有没有人见过这种类型的错误?我将如何解决这样的事情?感谢您的任何建议!

采纳答案by ?ime Vidas

Try this:

尝试这个:

(function ( $ ) { 

    // put all that "wl_alert" code here   

}( jQuery ));

So, the $variable is apparently corrupted, but the jQueryvariable should still refer to the jQuery object. (In normal circumstances, both the $and jQueryvariables refer to the (same) jQuery object.)

因此,该$变量显然已损坏,但该jQuery变量仍应引用 jQuery 对象。(在正常情况下,变量$jQuery变量都引用(相同的)jQuery 对象。)

Instead of having to replace the $name with the jQueryname in your entire code, you can simply use an IIFEto alias the name manually. So, the outside-variable jQueryis aliased with the $variable inside the function.

不必在整个代码$中用jQuery名称替换名称,您只需使用IIFE手动为名称设置别名。因此,外部变量jQuery$函数内部变量具有别名。

Here's a simple example to help you understand this concept:

下面是一个简单的例子来帮助你理解这个概念:

var foo = 'Peter';

(function ( bar ) {

    bar // evaluates to 'Peter'

}( foo ));

回答by Said El-Ghamri

try to call jQuery library before bootstrap.js

尝试在 bootstrap.js 之前调用 jQuery 库

<script src="js/jquery-3.3.1.min.js"></script>
<script src="js/bootstrap.min.js"></script>

回答by MarsPeople

If you get Cannot read property 'fn' of undefined, the problem may be you loading libraries in wrong order.

如果您得到无法读取 undefined 的属性 'fn',则问题可能是您以错误的顺序加载库

For example:

例如:

You should load bootstrap.jsfirst and then load bootstrap.jslibraries.

您应该先加载bootstrap.js,然后加载bootstrap.js库。

<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap3-dialog/1.34.7/js/bootstrap-dialog.min.js"></script>

回答by sanzmalz

Import the jquery CDNas a first

导入jQuery的CDN作为第一

(e.g)

(例如)

<script
  src="https://code.jquery.com/jquery-3.3.1.min.js"
  integrity="sha256-FgpCb/KJQlLNfOu91ta32o/NMZxltwRo8QtmkMRdAu8="
  crossorigin="anonymous"></script>

回答by Khachornchit Songsaen

I fixed it by added the jquery.slim.min.jsafter the jquery.min.js, as the Solution Sequence.

我通过在jquery.min.js之后添加jquery.slim.min.js作为解决方案序列来修复它。

Problem Sequence

问题序列

<script src="./vendor/jquery/jquery.min.js"></script>
<script src="./vendor/bootstrap/js/bootstrap.bundle.min.js"></script>

Solution Sequence

解决方案顺序

<script src="./vendor/jquery/jquery.min.js"></script>
<script src="./vendor/jquery/jquery.slim.min.js"></script>
<script src="./vendor/jquery-easing/jquery.easing.min.js"></script>

回答by MD Ashik

Ha ha ha Funny it's a simple mistake for me

哈哈哈 有趣的是对我来说这是一个简单的错误

I got asyncon my jquerylibrary call. Just remove it and I got solution.

我接到asyncjquery库调用。只需删除它,我就得到了解决方案。

<script async src="https://code.jquery.com/jquery-3.3.1.min.js"></script>

TO

<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>

Why it did this kind of behave:I got documentation on W3schools LINK

为什么会出现这种行为:我在 W3schools LINK上获得了文档

Definition and Usage async

定义和用法 async

The async attribute is a boolean attribute.

async 属性是一个布尔属性。

When present, it specifies that the script will be executed asynchronously as soon as it is available.

当存在时,它指定脚本一可用就异步执行。

Note:The async attribute is only for external scripts (and should only be used if the src attribute is present).

注意:async 属性仅适用于外部脚本(并且只应在 src 属性存在时使用)。

Note:There are several ways an external script can be executed:

注意:有几种方法可以执行外部脚本:

1.If async is present:The script is executed asynchronously with the rest of the page (the script will be executed while the page continues the parsing)

1.如果存在 async:脚本与页面的其余部分异步执行(脚本将在页面继续解析的同时执行)

2.If async is not present and defer is present:The script is executed when the page has finished parsing

2.如果async不存在而defer存在:当页面解析完成时执行脚本

3.If neither async or defer is present:The script is fetched and executed immediately, before the browser continues parsing the page

3.如果 async 或 defer 都不存在:在浏览器继续解析页面之前,立即获取并执行脚本

回答by Susha Denis

When I used Electron + Angular such order helped me to solve problem

当我使用 Electron + Angular 时,这样的命令帮助我解决了问题

  <script src="./assets/js/jquery-3.3.1.min.js"></script>
  <script src="./assets/js/jquery-3.3.1.slim.min.js"></script>
  <script src="./assets/js/popper.min.js"></script>
  <script src="./assets/js/bootstrap.min.js"></script>

回答by Victor Azevedo

You can use noConflict function:

您可以使用 noConflict 函数:

var JJ= jQuery.noConflict(); 
JJ('.back').click(function (){
    window.history.back();
}); 

Change all $ to JJ.

将所有 $ 更改为 JJ。

回答by Levi Josman

I too had the "Uncaught TypeError: Cannot read property 'fn' of undefined" with:

我也有“未捕获的类型错误:无法读取未定义的属性‘fn’”:

$.fn.circleType = function(options) {

CODE...

};

But fixed it by wrapping it in a document ready function:

但是通过将其包装在文档就绪函数中来修复它:

jQuery(document).ready.circleType = function(options) {

CODE...

};

回答by Napster777

I had the same problem and I did it this way

我有同样的问题,我是这样做的

//note that I added jquery separately above this

//注意我在这上面单独添加了jquery

<!--ENJOY HINT PACKAGES --START -->
<link href="path/enjoyhint/jquery.enjoyhint.css" rel="stylesheet">
<script src="path/enjoyhint/jquery.enjoyhint.js"></script>
<script src="path/enjoyhint/kinetic.min.js"></script>
<script src="path/enjoyhint/enjoyhint.js"></script>  
<!--ENJOY HINT PACKAGES --END -->

and it works

它有效