Java 在 Android 中发送 POST 数据
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Sending POST data in Android
提问by OMGKurtNilsen
I'm experienced with PHP, JavaScript and a lot of other scripting languages, but I don't have a lot of experience with Java or Android.
我对 PHP、JavaScript 和许多其他脚本语言有经验，但我对 Java 或 Android 没有很多经验。
I'm looking for a way to send POSTdata to a PHP script and display the result.
我正在寻找一种将POST数据发送到 PHP 脚本并显示结果的方法。
采纳答案by Primal Pappachan
* Updated Answer which works on Android 6.0+. Thanks to @Rohit Suthar, @Tamis Bolvariand @sudhiskrfor the comments. *
* 更新了适用于 Android 6.0+ 的答案。感谢@Rohit Suthar、@Tamis Bolvari和@sudhiskr的评论。*
public class CallAPI extends AsyncTask<String, String, String> {
public CallAPI(){
//set context variables if required
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected String doInBackground(String... params) {
String urlString = params[0]; // URL to call
String data = params[1]; //data to post
OutputStream out = null;
try {
URL url = new URL(urlString);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
out = new BufferedOutputStream(urlConnection.getOutputStream());
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, "UTF-8"));
writer.write(data);
writer.flush();
writer.close();
out.close();
urlConnection.connect();
} catch (Exception e) {
System.out.println(e.getMessage());
}
}
}
References:
参考：
- https://developer.android.com/reference/java/net/HttpURLConnection.html
- How to add parameters to HttpURLConnection using POST using NameValuePair
- https://developer.android.com/reference/java/net/HttpURLConnection.html
- 如何使用 NameValuePair 使用 POST 向 HttpURLConnection 添加参数
Older Answer
较旧的答案
Note: This solution is outdated. It only works on Android devices up to 5.1. Android 6.0 and above do not include the Apache http client used in this answer.
注意：此解决方案已过时。它仅适用于 5.1 以下的 Android 设备。Android 6.0 及更高版本不包括此答案中使用的 Apache http 客户端。
Http Client from Apache Commons is the way to go. It is already included in android. Here's a simple example of how to do HTTP Post using it.
来自 Apache Commons 的 Http Client 是要走的路。它已经包含在android中。这是一个如何使用它进行 HTTP Post 的简单示例。
public void postData() {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "Hi"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
回答by Matthew Flaschen
You can use URLConnectionwith setDoOutput(true), getOutputStream()(for sending data), andgetInputStream()(for receiving). Sun has an examplefor exactly this.
您可以使用URLConnectionwith , （用于发送数据）和（用于接收）。Sun 有一个例子来说明这一点。setDoOutput(true)getOutputStream()getInputStream()
回答by Toni Menzel
Better use Apache Commons HttpClient, that is also included in android already. Have a look at Android Developer: Apache HTTP Client Package Summaryfor general api info.
最好使用 Apache Commons HttpClient，它也已包含在 android 中。查看 Android Developer: Apache HTTP Client Package Summary了解一般 api 信息。
回答by Fabricio PH
to @primpop answer I would add how to convert the response in a String:
对于@primpop 答案，我将添加如何将响应转换为字符串：
HttpResponse response = client.execute(request);
HttpEntity entity = response.getEntity();
if (entity != null) {
InputStream instream = entity.getContent();
String result = RestClient.convertStreamToString(instream);
Log.i("Read from server", result);
}
回答by Andrey
This is an example of how to POST multi-part data WITHOUT using external Apache libraries:
这是如何在不使用外部 Apache 库的情况下发布多部分数据的示例：
byte[] buffer = getBuffer();
if(buffer.length > 0) {
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "RQdzAAihJq7Xp1kjraqf";
ByteArrayOutputStream baos = new ByteArrayOutputStream();
DataOutputStream dos = new DataOutputStream(baos);
// Send parameter #1
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param1\"" + lineEnd);
dos.writeBytes("Content-Type: text/plain; charset=US-ASCII" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: 8bit" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(myStringData + lineEnd);
// Send parameter #2
//dos.writeBytes(twoHyphens + boundary + lineEnd);
//dos.writeBytes("Content-Disposition: form-data; name=\"param2\"" + lineEnd + lineEnd);
//dos.writeBytes("foo2" + lineEnd);
// Send a binary file
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param3\";filename=\"test_file.dat\"" + lineEnd);
dos.writeBytes("Content-Type: application/octet-stream" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: binary" + lineEnd);
dos.writeBytes(lineEnd);
dos.write(buffer);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.flush();
dos.close();
ByteArrayInputStream content = new ByteArrayInputStream(baos.toByteArray());
BasicHttpEntity entity = new BasicHttpEntity();
entity.setContent(content);
HttpPost httpPost = new HttpPost(myURL);
httpPost.addHeader("Connection", "Keep-Alive");
httpPost.addHeader("Content-Type", "multipart/form-data; boundary="+boundary);
//MultipartEntity entity = new MultipartEntity();
//entity.addPart("param3", new ByteArrayBody(buffer, "test_file.dat"));
//entity.addPart("param1", new StringBody(myStringData));
httpPost.setEntity(entity);
/*
String httpData = "";
ByteArrayOutputStream baos1 = new ByteArrayOutputStream();
entity.writeTo(baos1);
httpData = baos1.toString("UTF-8");
*/
/*
Header[] hdrs = httpPost.getAllHeaders();
for(Header hdr: hdrs) {
httpData += hdr.getName() + " | " + hdr.getValue() + " |_| ";
}
*/
//Log.e(TAG, "httpPost data: " + httpData);
response = httpClient.execute(httpPost);
}
回答by Siddhpura Amit
By this way we can send data with http post method and get result
这样我们就可以用http post方法发送数据并得到结果
public class MyHttpPostProjectActivity extends Activity implements OnClickListener {
private EditText usernameEditText;
private EditText passwordEditText;
private Button sendPostReqButton;
private Button clearButton;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.login);
usernameEditText = (EditText) findViewById(R.id.login_username_editText);
passwordEditText = (EditText) findViewById(R.id.login_password_editText);
sendPostReqButton = (Button) findViewById(R.id.login_sendPostReq_button);
sendPostReqButton.setOnClickListener(this);
clearButton = (Button) findViewById(R.id.login_clear_button);
clearButton.setOnClickListener(this);
}
@Override
public void onClick(View v) {
if(v.getId() == R.id.login_clear_button){
usernameEditText.setText("");
passwordEditText.setText("");
passwordEditText.setCursorVisible(false);
passwordEditText.setFocusable(false);
usernameEditText.setCursorVisible(true);
passwordEditText.setFocusable(true);
}else if(v.getId() == R.id.login_sendPostReq_button){
String givenUsername = usernameEditText.getEditableText().toString();
String givenPassword = passwordEditText.getEditableText().toString();
System.out.println("Given username :" + givenUsername + " Given password :" + givenPassword);
sendPostRequest(givenUsername, givenPassword);
}
}
private void sendPostRequest(String givenUsername, String givenPassword) {
class SendPostReqAsyncTask extends AsyncTask<String, Void, String>{
@Override
protected String doInBackground(String... params) {
String paramUsername = params[0];
String paramPassword = params[1];
System.out.println("*** doInBackground ** paramUsername " + paramUsername + " paramPassword :" + paramPassword);
HttpClient httpClient = new DefaultHttpClient();
// In a POST request, we don't pass the values in the URL.
//Therefore we use only the web page URL as the parameter of the HttpPost argument
HttpPost httpPost = new HttpPost("http://www.nirmana.lk/hec/android/postLogin.php");
// Because we are not passing values over the URL, we should have a mechanism to pass the values that can be
//uniquely separate by the other end.
//To achieve that we use BasicNameValuePair
//Things we need to pass with the POST request
BasicNameValuePair usernameBasicNameValuePair = new BasicNameValuePair("paramUsername", paramUsername);
BasicNameValuePair passwordBasicNameValuePAir = new BasicNameValuePair("paramPassword", paramPassword);
// We add the content that we want to pass with the POST request to as name-value pairs
//Now we put those sending details to an ArrayList with type safe of NameValuePair
List<NameValuePair> nameValuePairList = new ArrayList<NameValuePair>();
nameValuePairList.add(usernameBasicNameValuePair);
nameValuePairList.add(passwordBasicNameValuePAir);
try {
// UrlEncodedFormEntity is an entity composed of a list of url-encoded pairs.
//This is typically useful while sending an HTTP POST request.
UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(nameValuePairList);
// setEntity() hands the entity (here it is urlEncodedFormEntity) to the request.
httpPost.setEntity(urlEncodedFormEntity);
try {
// HttpResponse is an interface just like HttpPost.
//Therefore we can't initialize them
HttpResponse httpResponse = httpClient.execute(httpPost);
// According to the JAVA API, InputStream constructor do nothing.
//So we can't initialize InputStream although it is not an interface
InputStream inputStream = httpResponse.getEntity().getContent();
InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
StringBuilder stringBuilder = new StringBuilder();
String bufferedStrChunk = null;
while((bufferedStrChunk = bufferedReader.readLine()) != null){
stringBuilder.append(bufferedStrChunk);
}
return stringBuilder.toString();
} catch (ClientProtocolException cpe) {
System.out.println("First Exception caz of HttpResponese :" + cpe);
cpe.printStackTrace();
} catch (IOException ioe) {
System.out.println("Second Exception caz of HttpResponse :" + ioe);
ioe.printStackTrace();
}
} catch (UnsupportedEncodingException uee) {
System.out.println("An Exception given because of UrlEncodedFormEntity argument :" + uee);
uee.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
if(result.equals("working")){
Toast.makeText(getApplicationContext(), "HTTP POST is working...", Toast.LENGTH_LONG).show();
}else{
Toast.makeText(getApplicationContext(), "Invalid POST req...", Toast.LENGTH_LONG).show();
}
}
}
SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
sendPostReqAsyncTask.execute(givenUsername, givenPassword);
}
}
回答by Muhammad Aamir Ali
Method to post data as HTTP request,
将数据作为 HTTP 请求发布的方法，
public static InputStream callPostService(String Url,
List<NameValuePair> data) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(Url);
try {
httppost.setEntity(new UrlEncodedFormEntity(data));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
return entity.getContent();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
回答by user2312638
In newer versions of Android you have to put all web I/O requests into a new thread. AsyncTask works best for small requests.
在较新版本的 Android 中，您必须将所有 Web I/O 请求放入一个新线程中。AsyncTask 最适合小请求。
回答by Selim Raza
You can use this to send an HTTP POST request to a URL. You can easily send request and get response. I always use this . I fine work to me.
您可以使用它向 URL 发送 HTTP POST 请求。您可以轻松发送请求并获得响应。我总是用这个。我对我很好。
///////////////////// Check SubScription ////////////////////
try {
AsyncHttpClient client = new AsyncHttpClient();
// Http Request Params Object
RequestParams params = new RequestParams();
String u = "B2mGaME";
String au = "gamewrapperB2M";
// String mob = "880xxxxxxxxxx";
params.put("usr", u.toString());
params.put("aut", au.toString());
params.put("uph", MobileNo.toString());
// params.put("uph", mob.toString());
client.post("http://196.6.13.01:88/ws/game_wrapper_reg_check.php", params, new AsyncHttpResponseHandler() {
@Override
public void onSuccess(String response) {
playStatus = response;
//////Get your Response/////
Log.i(getClass().getSimpleName(), "Response SP Status. " + playStatus);
}
@Override
public void onFailure(Throwable throwable) {
super.onFailure(throwable);
}
});
} catch (Exception e) {
e.printStackTrace();
}
You Also need to Add bellow Jar file in libs folde
您还需要在 libs 文件夹中添加波纹管 Jar 文件
android-async-http-1.3.1.jar
Finally edit your build.gradle
最后编辑你的 build.gradle
dependencies {
compile files('libs/<android-async-http-1.3.1.jar>')
}
In the last Rebuild your project.
在最后重建你的项目。
回答by Adnan Abdollah Zaki
for Android = > 5
为的Android => 5
The org.apache.httpclasses and the AndroidHttpClientclass have been deprecatedin Android 5.1. These classes are no longer being maintained and you should migrate any app code using these APIs to the URLConnectionclasses as soon as possible.
该org.apache.http类和AndroidHttpClient类已经被弃用的是Android 5.1。这些类不再维护，您应该尽快将使用这些 API 的任何应用程序代码迁移到URLConnection类。
https://developer.android.com/about/versions/android-5.1.html#http
https://developer.android.com/about/versions/android-5.1.html#http
Thought of sharing my code using HttpUrlConnection
使用HttpUrlConnection分享我的代码的想法
public String performPostCall(String requestURL,
HashMap<String, String> postDataParams) {
URL url;
String response = "";
try {
url = new URL(requestURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(15000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("GET");
conn.setDoInput(true);
conn.setDoOutput(true);
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
writer.write(getPostDataString(postDataParams));
writer.flush();
writer.close();
os.close();
int responseCode=conn.getResponseCode();
if (responseCode == HttpsURLConnection.HTTP_OK) {
String line;
BufferedReader br=new BufferedReader(new InputStreamReader(conn.getInputStream()));
while ((line=br.readLine()) != null) {
response+=line;
}
}
else {
response="";
}
} catch (Exception e) {
e.printStackTrace();
}
return response;
}
...
...
private String getPostDataString(HashMap<String, String> params) throws UnsupportedEncodingException{
StringBuilder result = new StringBuilder();
boolean first = true;
for(Map.Entry<String, String> entry : params.entrySet()){
if (first)
first = false;
else
result.append("&");
result.append(URLEncoder.encode(entry.getKey(), "UTF-8"));
result.append("=");
result.append(URLEncoder.encode(entry.getValue(), "UTF-8"));
}
return result.toString();
}
also you can Postmethod :
你也可以发布方法：
conn.setRequestMethod("POST");
Update 21/02/2016
21/02/2016 更新
for postrequest with json, see this example :
对于带有json 的post请求，请参见此示例：
public class Empty extends
AsyncTask<Void, Void, Boolean> {
String urlString = "http://www.yoursite.com/";
private final String TAG = "post json example";
private Context context;
private int advertisementId;
public Empty(Context contex, int advertisementId) {
this.context = contex;
this.advertisementId = advertisementId;
}
@Override
protected void onPreExecute() {
Log.e(TAG, "1 - RequestVoteTask is about to start...");
}
@Override
protected Boolean doInBackground(Void... params) {
boolean status = false;
String response = "";
Log.e(TAG, "2 - pre Request to response...");
try {
response = performPostCall(urlString, new HashMap<String, String>() {
private static final long serialVersionUID = 1L;
{
put("Accept", "application/json");
put("Content-Type", "application/json");
}
});
Log.e(TAG, "3 - give Response...");
Log.e(TAG, "4 " + response.toString());
} catch (Exception e) {
// displayLoding(false);
Log.e(TAG, "Error ...");
}
Log.e(TAG, "5 - after Response...");
if (!response.equalsIgnoreCase("")) {
try {
Log.e(TAG, "6 - response !empty...");
//
JSONObject jRoot = new JSONObject(response);
JSONObject d = jRoot.getJSONObject("d");
int ResultType = d.getInt("ResultType");
Log.e("ResultType", ResultType + "");
if (ResultType == 1) {
status = true;
}
} catch (JSONException e) {
// displayLoding(false);
// e.printStackTrace();
Log.e(TAG, "Error " + e.getMessage());
} finally {
}
} else {
Log.e(TAG, "6 - response is empty...");
status = false;
}
return status;
}
@Override
protected void onPostExecute(Boolean result) {
//
Log.e(TAG, "7 - onPostExecute ...");
if (result) {
Log.e(TAG, "8 - Update UI ...");
// setUpdateUI(adv);
} else {
Log.e(TAG, "8 - Finish ...");
// displayLoding(false);
// finish();
}
}
public String performPostCall(String requestURL,
HashMap<String, String> postDataParams) {
URL url;
String response = "";
try {
url = new URL(requestURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(context.getResources().getInteger(
R.integer.maximum_timeout_to_server));
conn.setConnectTimeout(context.getResources().getInteger(
R.integer.maximum_timeout_to_server));
conn.setRequestMethod("POST");
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setRequestProperty("Content-Type", "application/json");
Log.e(TAG, "11 - url : " + requestURL);
/*
* JSON
*/
JSONObject root = new JSONObject();
//
String token = Static.getPrefsToken(context);
root.put("securityInfo", Static.getSecurityInfo(context));
root.put("advertisementId", advertisementId);
Log.e(TAG, "12 - root : " + root.toString());
String str = root.toString();
byte[] outputBytes = str.getBytes("UTF-8");
OutputStream os = conn.getOutputStream();
os.write(outputBytes);
int responseCode = conn.getResponseCode();
Log.e(TAG, "13 - responseCode : " + responseCode);
if (responseCode == HttpsURLConnection.HTTP_OK) {
Log.e(TAG, "14 - HTTP_OK");
String line;
BufferedReader br = new BufferedReader(new InputStreamReader(
conn.getInputStream()));
while ((line = br.readLine()) != null) {
response += line;
}
} else {
Log.e(TAG, "14 - False - HTTP_OK");
response = "";
}
} catch (Exception e) {
e.printStackTrace();
}
return response;
}
}
UPDATE 24/08/2016
更新 24/08/2016
Use some best library , such as :
使用一些最好的库，例如：
because :
因为 ：
- Avoid HttpUrlConnection and HttpClient
- 避免 HttpUrlConnection 和 HttpClient
On lower API levels (mostly on Gingerbread and Froyo), HttpUrlConnection and HttpClient are far from being perfect
在较低的 API 级别（主要是在 Gingerbread 和 Froyo 上），HttpUrlConnection 和 HttpClient 远非完美
- And Avoid AsyncTask Too
- They are Much Faster
- They Caches Everything
- 并避免 AsyncTask
- 他们要快得多
- 他们缓存一切
Since the introduction of Honeycomb (API 11), it's been mandatory to perform network operations on a separate thread, different from the main thread
自 Honeycomb (API 11) 引入以来，必须在与主线程不同的单独线程上执行网络操作
