C# 从另一个列表中排除包含值的列表项
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时间：2020-08-09 17:05:57 来源:igfitidea点击:
Exclude list items that contain values from another list
提问by lekso
There are two lists:
有两个列表：
List<string> excluded = new List<string>() { ".pdf", ".jpg" };
List<string> dataset = new List<string>() {"valid string", "invalid string.pdf", "invalid string2.jpg","valid string 2.xml" };
How can I filter-out values from the "dataset" list which contain any keyword from the "excluded" list?
如何从“数据集”列表中过滤掉包含“排除”列表中任何关键字的值？
采纳答案by MarcinJuraszek
var results = dataset.Where(i => !excluded.Any(e => i.Contains(e)));
回答by abatishchev
Try:
尝试：
var result = from s in dataset
from e in excluded
where !s.Contains(e)
select e;
回答by M_Farahmand
var result=dataset.Where(x=>!excluded.Exists(y=>x.Contains(y)));
This also works when excluded list is empty.
这在排除列表为空时也有效。
回答by Majid Shahmohammadi
// Contains four values.
int[] values1 = { 1, 2, 3, 4 };
// Contains three values (1 and 2 also found in values1).
int[] values2 = { 1, 2, 5 };
// Remove all values2 from values1.
var result = values1.Except(values2);
回答by Kyle Zhao
var result = dataset.Where(x => !excluded.Contains(x));
var 结果 = dataset.Where(x => !excluded.Contains(x));
