C# 如何从嵌入式资源中提取文件并将其保存到磁盘?

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/13031778/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-10 01:24:22  来源:igfitidea点击:

How can I extract a file from an embedded resource and save it to disk?

c#.netembedded-resourcecsharpcodeprovider

提问by Rafik Bari

I'm trying to compile the code below using CSharpCodeProvider. The file is successfully compiled, but when I click on the generated EXE file, I get an error (Windows is searching for a solution to this problem) and nothing happens.

我正在尝试使用 CSharpCodeProvider 编译下面的代码。该文件已成功编译,但是当我单击生成的 EXE 文件时,出现错误(Windows 正在寻找此问题的解决方案)并且没有任何反应。

When I compile the code below using CSharpCodeProvider, I've added the MySql.Data.dllas an embedded resource file using this line of code:

当我使用 CSharpCodeProvider 编译下面的代码时,我使用以下代码行将其添加MySql.Data.dll为嵌入式资源文件:

if (provider.Supports(GeneratorSupport.Resources))
    cp.EmbeddedResources.Add("MySql.Data.dll");

The file is successfully embedded (because I noticed the file size increased).

文件已成功嵌入(因为我注意到文件大小增加了)。

In the code below, I try to extract the embedded DLL file and save it to System32, but the code below doesn't work for some reason.

在下面的代码中,我尝试提取嵌入的 DLL 文件并将其保存到 System32,但由于某些原因,下面的代码不起作用。

namespace ConsoleApplication1
{
    class Program
    {
        public static void ExtractSaveResource(String filename, String location)
        {
            //Assembly assembly = Assembly.GetExecutingAssembly();
            Assembly a = .Assembly.GetExecutingAssembly();
            //Stream stream = assembly.GetManifestResourceStream("Installer.Properties.mydll.dll"); // or whatever
            //string my_namespace = a.GetName().Name.ToString();
            Stream resFilestream = a.GetManifestResourceStream(filename);
            if (resFilestream != null)
            {
                BinaryReader br = new BinaryReader(resFilestream);
                FileStream fs = new FileStream(location, FileMode.Create); // Say
                BinaryWriter bw = new BinaryWriter(fs);
                byte[] ba = new byte[resFilestream.Length];
                resFilestream.Read(ba, 0, ba.Length);
                bw.Write(ba);
                br.Close();
                bw.Close();
                resFilestream.Close();
            }
            // this.Close();
        }

        static void Main(string[] args)
        {
            try
            {
                string systemDir = Environment.SystemDirectory;
                ExtractSaveResource("MySql.Data.dll", systemDir);
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
                Console.ReadKey();
            }
        }
    }
}

How can I extract the DLL file that is embedded as a resource and save it to System32?

如何提取作为资源嵌入的DLL文件并将其保存到System32?

采纳答案by Thomas Sapp

I have found that the easiest way to do this is to use Properties.Resourcesand File. Here is the code I use (requires using System.IO)...

我发现最简单的方法是使用Properties.ResourcesFile。这是我使用的代码(需要using System.IO)...

For Binary files: File.WriteAllBytes(fileName, Properties.Resources.file);

对于二进制文件: File.WriteAllBytes(fileName, Properties.Resources.file);

For Text files: File.WriteAllText(fileName, Properties.Resources.file);

对于文本文件: File.WriteAllText(fileName, Properties.Resources.file);

回答by Paul Aldred-Bann

Try reading your target assembly into a MemoryStreamand then saving to a FileStreamlike this (please bear in mind that this code isn't tested):

尝试将目标程序集读入 aMemoryStream然后FileStream像这样保存到 a (请记住,此代码未经过测试):

Assembly assembly = Assembly.GetExecutingAssembly();

using (var target = assembly.GetManifestResourceStream("MySql.Data.dll"))
{
    var size = target.CanSeek ? Convert.ToInt32(target.Length) : 0;

    // read your target assembly into the MemoryStream
    MemoryStream output = null;
    using (output = new MemoryStream(size))
    {
        int len;
        byte[] buffer = new byte[2048];

        do
        {
            len = target.Read(buffer, 0, buffer.Length);
            output.Write(buffer, 0, len);
        } 
        while (len != 0);
    }

    // now save your MemoryStream to a flat file
    using (var fs = File.OpenWrite(@"c:\Windows\System32\MySql.Data.dll"))
    {
        output.WriteTo(fs);
        fs.Flush();
        fs.Close()
    }
}

回答by M ten Klooster

I've been using this (tested) method:

我一直在使用这种(经过测试的)方法:

OutputDir: Location where you want to copy the resource

OutputDir:要复制资源的位置

ResourceLocation: Namespace (+ dirnames)

ResourceLocation:命名空间(+ 目录名)

Files: List of files within the resourcelocation, you want to copy.

文件:资源位置中要复制的文件列表。

    private static void ExtractEmbeddedResource(string outputDir, string resourceLocation, List<string> files)
    {
        foreach (string file in files)
        {
            using (System.IO.Stream stream = System.Reflection.Assembly.GetExecutingAssembly().GetManifestResourceStream(resourceLocation + @"." + file))
            {
                using (System.IO.FileStream fileStream = new System.IO.FileStream(System.IO.Path.Combine(outputDir, file), System.IO.FileMode.Create))
                {
                    for (int i = 0; i < stream.Length; i++)
                    {
                        fileStream.WriteByte((byte)stream.ReadByte());
                    }
                    fileStream.Close();
                }
            }
        }
    }

回答by Piotr Zierhoffer

I'd suggest doing it easier. I assume that the resource exists and the file is writable (this might be an issue if we're speaking about system directories).

我建议做得更容易。我假设资源存在并且文件是可写的(如果我们谈论的是系统目录,这可能是一个问题)。

public void WriteResourceToFile(string resourceName, string fileName)
{
    using(var resource = Assembly.GetExecutingAssembly().GetManifestResourceStream(resourceName))
    {
        using(var file = new FileStream(fileName, FileMode.Create, FileAccess.Write))
        {
            resource.CopyTo(file);
        } 
    }
}

回答by Diego Fortes

This works perfectly!

这工作得很好!

public static void Extract(string nameSpace, string outDirectory, string internalFilePath, string resourceName)
{
    //nameSpace = the namespace of your project, located right above your class' name;
    //outDirectory = where the file will be extracted to;
    //internalFilePath = the name of the folder inside visual studio which the files are in;
    //resourceName = the name of the file;
    Assembly assembly = Assembly.GetCallingAssembly();

    using (Stream s = assembly.GetManifestResourceStream(nameSpace + "." + (internalFilePath == "" ? "" : internalFilePath + ".") + resourceName))
    using (BinaryReader r = new BinaryReader(s))
    using (FileStream fs = new FileStream(outDirectory + "\" + resourcename, FileMode.OpenOrCreate))
    using (BinaryWriter w = new BinaryWriter(fs))
    {
        w.Write(r.ReadBytes((int)s.Length));
    }
}

Example of usage:

用法示例:

public static void ExtractFile()
{
    String local = Environment.CurrentDirectory; //gets current path to extract the files

    Extract("Geral", local, "Arquivos", "bloquear_vbs.vbs");
}    

If this still doesn't help, try this video out: https://www.youtube.com/watch?v=_61pLVH2qPk

如果这仍然没有帮助,试试这个视频:https: //www.youtube.com/watch?v=_61pLVH2qPk

回答by BillKrat

Or using an extension method...

或者使用扩展方法...

 /// <summary>
 /// Retrieves the specified [embedded] resource file and saves it to disk.  
 /// If only filename is provided then the file is saved to the default 
 /// directory, otherwise the full filepath will be used.
 /// <para>
 /// Note: if the embedded resource resides in a different assembly use that
 /// assembly instance with this extension method.
 /// </para>
 /// </summary>
 /// <example>
 /// <code>
 ///       Assembly.GetExecutingAssembly().ExtractResource("Ng-setup.cmd");
 ///       OR
 ///       Assembly.GetExecutingAssembly().ExtractResource("Ng-setup.cmd", "C:\temp\MySetup.cmd");
 /// </code>
 /// </example>
 /// <param name="assembly">The assembly.</param>
 /// <param name="resourceName">Name of the resource.</param>
 /// <param name="fileName">Name of the file.</param>
 public static void ExtractResource(this Assembly assembly, string filename, string path=null)
 {
     //Construct the full path name for the output file
     var outputFile = path ?? $@"{Directory.GetCurrentDirectory()}\{filename}";

     // If the project name contains dashes replace with underscores since 
     // namespaces do not permit dashes (underscores will be default to).
     var resourceName = $"{assembly.GetName().Name.Replace("-","_")}.{filename}";

     // Pull the fully qualified resource name from the provided assembly
     using (var resource = assembly.GetManifestResourceStream(resourceName))
     {
         if (resource == null)
             throw new FileNotFoundException($"Could not find [{resourceName}] in {assembly.FullName}!");

         using (var file = new FileStream(outputFile, FileMode.Create, FileAccess.Write))
         {
             resource.CopyTo(file);
         }
     }
 }