C#：如何将 long 转换为 ulong
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C#: How to convert long to ulong
提问by Ivan Prodanov
If i try with BitConverter,it requires a byte array and i don't have that.I have a Int32 and i want to convert it to UInt32.
如果我尝试使用 BitConverter，它需要一个字节数组，而我没有。我有一个 Int32，我想将它转换为 UInt32。
In C++ there was no problem with that.
在 C++ 中，这没有问题。
采纳答案by Matthew Olenik
A simple cast is all you need. Since it's possible to lose precision doing this, the conversion is explicit.
您只需要一个简单的演员表即可。由于这样做可能会失去精度，因此转换是显式的。
long x = 10;
ulong y = (ulong)x;
回答by Chris
To convert a long to a ulong, simply cast it:
要将 long 转换为 ulong，只需将其强制转换：
long a;
ulong b = (ulong)a;
C# will NOT throw an exception if it is a negative number.
如果它是负数，C# 不会抛出异常。
回答by SirDemon
Try:
尝试：
Convert.ToUInt32()
回答by Mitch Wheat
Int32 i = 17;
UInt32 j = (UInt32)i;
EDIT: question is unclear whether you have a long or an int?
编辑：问题不清楚你是 long 还是 int？
回答by intrepidis
Given this function:
鉴于此功能：
string test(long vLong)
{
ulong vULong = (ulong)vLong;
return string.Format("long hex: {0:X}, ulong hex: {1:X}", vLong, vULong);
}
And this usage:
而这种用法：
string t1 = test(Int64.MinValue);
string t2 = test(Int64.MinValue + 1L);
string t3 = test(-1L);
string t4 = test(-2L);
This will be the result:
这将是结果：
t1 == "long hex: 8000000000000000, ulong hex: 8000000000000000"
t2 == "long hex: 8000000000000001, ulong hex: 8000000000000001"
t3 == "long hex: FFFFFFFFFFFFFFFF, ulong hex: FFFFFFFFFFFFFFFF"
t4 == "long hex: FFFFFFFFFFFFFFFE, ulong hex: FFFFFFFFFFFFFFFE"
As you can see the bits are preserved completely, even for negative values.
如您所见，即使对于负值，位也被完全保留。
