php json_encode 不使用 html 字符串作为值
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json_encode not working with a html string as value
提问by planet x
I am debugging this ajax for quite a time now. I have this on my jQUery file:
我调试这个 ajax 已经有一段时间了。我的 jQUEry 文件中有这个：
$("#typeForm").ajaxForm({
success : function(html){
alert(html);
}).submit();
This calls service.php, and within it I have this:
这称为service.php，其中我有这个：
$data = array('upload_data' => $this->upload->data());
$str = "<div style='position:relative'><img src='/assets/ui/success.png' /><span style='position:relative;top:-15px;'>Nachricht empfangen!</span></div>";
echo json_encode(array('file_name' => $data['upload_data']['file_name'], 'prompt' => $str));
This won't work. But by replacing $strto $str = "HELLO WORLD";the jQuery alerts what should I expected. What seems to be the problem?
这行不通。但通过更换$str到$str = "HELLO WORLD";了jQuery提醒我所期待的应该。似乎是什么问题？
EDIT:
编辑：
Here is a screenie of the output:
这是输出的屏幕：
It does alerts, but if I modify my jQuery into this:
它会发出警报，但是如果我将 jQuery 修改为：
$("#typeForm").ajaxForm({
success : function(html){
var obj = $.parseJSON(html);
alert(obj);
}).submit();
Then it does nothing at all, even alerting.
然后它什么也不做，甚至发出警报。
I did a var_dump on the json_encodeand here is the dump, it looks like a malformed JSON:
我做了一个 var_dump json_encode，这里是转储，它看起来像一个格式错误的 JSON：
string(214) "{"file_name":"cde595988d386529909ce5a8fe3a6d6f.png","prompt":"<div style="position:relative;"><img src="\/assets\/ui\/success.png" \=""><span style="position:relative;top:-15px;">Nachricht empfangen!<\/span><\/div>"}"
</span></div>
Here is the full content of service.php
这里是service.php的全部内容
class Service extends CI_Controller
{
public function __construct()
{
parent::__construct();
}
public function index()
{
$filename = 'uploadfile';
$config['upload_path'] = './uploads/temp';
$config['allowed_types'] = 'jpg|png|gif|doc|docx|pdf|ppt|pptx|xls|xlsx|bmp';
$config['max_size'] = '3072';
$config['encrypt_name'] = TRUE;
$config['remove_spaces'] = TRUE;
$this->load->library('upload', $config);
if (!$this->upload->do_upload($filename))
{
$error = array('error' => $this->upload->display_errors());
echo json_encode(array('error' => $error['error']));
}
else
{
$data = array('upload_data' => $this->upload->data());
$file_name = $data['upload_data']['file_name'];
//print_r($data);
//echo json_encode(array('test' => "Hello World"));
$str = "<div style='position:relative;'><img src='/assets/ui/success.png' /><span style='position:relative;top:-15px;'>Nachricht empfangen!</span></div>";
$str2 = json_encode(array("file_name" => $file_name, "prompt" => $str));
//var_dump($str2);
exit(json_encode(array('file_name' => $data['upload_data']['file_name'], 'prompt' => $str)));
}
}
}
回答by Abhishek Sachan
I was having same problem with json_encodetoday. But after testing a lot I found the correct solution:
我json_encode今天遇到了同样的问题。但经过大量测试后，我找到了正确的解决方案：
In PHP to encode the array or string:
在 PHP 中对数组或字符串进行编码：
json_encode($array, JSON_HEX_QUOT | JSON_HEX_TAG);
In JS to decode the same:
在JS中解码相同：
var d = $.parseJSON(content);
回答by Andreas Wong
Some stuff to try:
一些尝试的东西：
ajaxForm supports dataType argument, if you expect a JSON coming from the server, use dataType: jsonlike so
ajaxForm 支持 dataType 参数，如果您希望来自服务器的 JSON，请dataType: json像这样使用
$("#typeForm").ajaxForm({
success : function(html){
// html here is already automatically a json object
alert(html.prompt);
},
dataType: 'json'
}).submit();
Could you post the full service.php? OR try the following:
你能发布完整的service.php吗？或尝试以下操作：
exit(json_encode(array('file_name' => $data['upload_data']['file_name'], 'prompt' => $str)));
exit(json_encode(array('file_name' => $data['upload_data']['file_name'], 'prompt' => $str)));
-- EDIT --
- 编辑 -
Not sure why json_encode returns such weird string :s, is the json_encodea standard php library or an external library? I'm asking this because some servers don't have json_encode in their php installation... I tested on my local and using php internal json_encode and it works fine:
不知道为什么 json_encode 返回如此奇怪的字符串：s，是json_encode标准的 php 库还是外部库？我问这个是因为有些服务器在他们的 php 安装中没有 json_encode ......我在我的本地测试并使用 php 内部 json_encode 并且它工作正常：
<?php
$str = "<div style='position:relative'><img src='/assets/ui/success.png' /><span style='position:relative;top:-15px;'>Nachricht empfangen!</span></div>";
echo json_encode(array('prompt' => $str));
// output
//{"prompt":"<div style='position:relative'><img src='\/assets\/ui\/success.png' \/><span style='position:relative;top:-15px;'>Nachricht empfangen!<\/span><\/div>"}
回答by Andrew
How about convert all the potential problem characters instead of just what fixes the problem in this circumstance:
在这种情况下，如何转换所有潜在的问题字符，而不仅仅是解决问题的字符：
die(json_encode($data, JSON_HEX_TAG | JSON_HEX_APOS | JSON_HEX_QUOT | JSON_HEX_AMP | JSON_UNESCAPED_UNICODE));
http://php.net/manual/en/function.json-encode.php
http://php.net/manual/en/function.json-encode.php
回答by Mohammad Fathi MiMFa
You should call only promptobject of your array not all! like below:
您应该只调用prompt数组的对象而不是全部！像下面这样：
$("#typeForm").ajaxForm({
success : function(html){
var obj = $.parseJSON(html);
alert(obj.prompt);
}).submit();
回答by jerjer
If you cannot find a better solution for this you can encode the value to base64 encoding:
如果您找不到更好的解决方案，您可以将值编码为 base64 编码：
$data = array('upload_data' => $this->upload->data());
$str = base64_encode("<div style='position:relative'><img src='/assets/ui/success.png' /><span style='position:relative;top:-15px;'>Nachricht empfangen!</span></div>");
echo json_encode(array('file_name' => $data['upload_data']['file_name'], 'prompt' => $str));
and in the client decode it, IMO this is more safer this is also more applicable if you're processing characters from different languages.
并且在客户端解码它时，IMO 这更安全，如果您正在处理来自不同语言的字符，这也更适用。
ALSO:
还：
to sure that no other characters will be added on the json string call exit;writer after you print it.
确保不会在 json 字符串调用出口上添加其他字符；打印后的作家。
回答by Kuba Paczyński
JSON doesn't play well with stringoutput that comes out of magic method __toString()- it nearly impossible to json_encode()anything that even remotely touched something like this.
JSON 不能很好地处理string来自魔法方法的输出__toString()- 几乎不可能对json_encode()任何甚至远程触及这样的东西的东西。
<?php
/**
* DEBUGGING NIGHTMARE
* SO MUCH FUN, 10/10,
*/
class Nightmare {
protected $str;
public function __construct($str) {
$this->str = $str;
}
public function __toString() {
return $this->str;
}
}
$test = new Nightmare('Hello Friends.');
echo $test;
> Hello Friends.
// cooool, so let's JSON the hell out of it, EASY
echo json_encode(['our_hello' => $test]);
// This what you expect to get, right?
> {"our_hello":"Hello Friends."}
// HAHA NO!!!
// THIS IS WHAT YOU GET:
> {"our_hello":{}}
// and this is why is that:
var_dump($test);
object(Nightmare)#1 (1) {
["str":protected]=>
string(14) "Hello Friends."
}
print_r($test);
Nightmare Object
(
[str:protected] => Hello Friends.
)
回答by AlfredoVR
string(214) "{"file_name":"cde595988d386529909ce5a8fe3a6d6f.png","prompt":"<div style="position:relative;"><img src="\/assets\/ui\/success.png" \=""><span style="position:relative;top:-15px;">Nachricht empfangen!<\/span><\/div>"}"
</span></div>
This seems to be broken because there's no quote escaping. When an unescaped " is found, it breaks the JSON structure you expect. Escaped " should be \", single quotes with \' and so on.
这似乎被打破了，因为没有引用转义。当找到未转义的 " 时，它会破坏您期望的 JSON 结构。转义的 " 应该是 \"，单引号和 \' 等。
回答by davehale23
It looks like you need to escape your quotes server-side. Since they are in there, it seems to be creating an invalid JSON string.
看起来您需要在服务器端转义报价。由于它们在那里，它似乎正在创建一个无效的 JSON 字符串。
