python 在python中将异常保存到文件
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save Exceptions to file in python
提问by Joschua
I want to save all following Exceptions in a file. The reason why I need this is because the IDLE for python 3.1.1 in Ubuntu raises an Exception at calltipps, but close to fast, that it isn't readble. Also I need this for testing. The best, would be if I just call a function which saves all Exception to a file. Thank you! ;)
我想将所有以下异常保存在一个文件中。我需要这个的原因是因为 Ubuntu 中 python 3.1.1 的 IDLE 在 calltipps 上引发了一个异常，但接近于快速，它不可读。我也需要这个来测试。最好的情况是，如果我只是调用一个将所有异常保存到文件的函数。谢谢！;)
// edit:
// 编辑：
i had looked first for a more general way! so that you do not have to place your whole code in a function or indentation. but now that worked wery well for me. although I would be still grateful, if you find a way!
我首先寻找更通用的方法！这样您就不必将整个代码放在函数或缩进中。但现在这对我来说效果很好。如果您找到方法，我仍然会感激不尽！
thanks!
谢谢！
回答by Ned Batchelder
If you have a convenient main()function (whatever it's called), then you can use the logging module:
如果你有一个方便的main()函数（不管它叫什么），那么你可以使用日志模块：
import logging
def main():
raise Exception("Hey!")
logging.basicConfig(level=logging.DEBUG, filename='/tmp/myapp.log')
try:
main()
except:
logging.exception("Oops:")
logging.exceptionconveniently gets the current exception and puts the details in the log:
logging.exception方便地获取当前异常并将详细信息放入日志中：
ERROR:root:Oops:
Traceback (most recent call last):
File "C:\foo\foo.py", line 9, in <module>
main()
File "C:\foo\foo.py", line 4, in main
raise Exception("Hey!")
Exception: Hey!
