Python：OSError：[Errno 2] 没有那个文件或目录：''

Python: OSError: [Errno 2] No such file or directory: ''

提问by Hugolpz

I have a 100 lines, 3 years old python scraper that now bug. Starting lines are:

我有一个 100 行、3 岁的 python 刮板，现在是错误的。起跑线是：

import urllib, re, os, sys, time    # line 1: import modules
os.chdir(os.path.dirname(sys.argv[0])) # line 2: all works in script's folder > relative address
# (rest of my script here!)

When run,

跑的时候，

$cd /my/folder/
$python script.py

I receive the error:

我收到错误：

python script.py 
Traceback (most recent call last):
  File "script.py", line 2, in <module>
    os.chdir(os.path.dirname(sys.argv[0]))
OSError: [Errno 2] No such file or directory: ''

How should I read this error and what to do ?

我应该如何阅读此错误以及该怎么做？

采纳答案by zigg

Have you noticed that you don't get the error if you run

你有没有注意到，如果你运行，你不会得到错误

python ./script.py

instead of

代替

python script.py

This is because sys.argv[0]will read ./script.pyin the former case, which gives os.path.dirnamesomething to work with. When you don't specify a path, sys.argv[0]reads simply script.py, and os.path.dirnamecannot determine a path.

这是因为sys.argv[0]will read./script.py在前一种情况下，它提供了os.path.dirname一些可以使用的东西。不指定路径时，只sys.argv[0]读取script.py，os.path.dirname无法确定路径。

回答by Martijn Pieters

Use os.path.abspath():

使用os.path.abspath()：

os.chdir(os.path.dirname(os.path.abspath(sys.argv[0])))

sys.argv[0]in your case is justa script name, no directory, so os.path.dirname()returns an empty string.

sys.argv[0]在你的情况下只是一个脚本名称，没有目录，所以os.path.dirname()返回一个空字符串。

os.path.abspath()turns that into a proper absolute path with directory name.

os.path.abspath()将其转换为带有目录名称的正确绝对路径。

回答by Moebius

I had this error because I was providing a string of arguments to subprocess.callinstead of an array of arguments. To prevent this, use shlex.split:

我有这个错误，因为我提供了一个参数字符串subprocess.call而不是一个参数数组。为了防止这种情况，请使用shlex.split：

import shlex, subprocess
command_line = "ls -a"
args = shlex.split(command_line)
p = subprocess.Popen(args)