Python 如何从pathlib.path获取给定文件所在的文件夹名称？
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How to get folder name, in which given file resides, from pathlib.path?
提问by trainset
Is there something similar to os.path.dirname(path), but in pathlib?
是否有类似于os.path.dirname(path), 但在 pathlib 中的东西？
采纳答案by larsks
It looks like there is a parentselement that contains all the parent directories of a given path. E.g., if you start with:
看起来有一个parents元素包含给定路径的所有父目录。例如，如果您从以下内容开始：
>>> import pathlib
>>> p = pathlib.Path('/path/to/my/file')
Then p.parents[0]is the directory containing file:
然后p.parents[0]是包含file以下内容的目录：
>>> p.parents[0]
PosixPath('/path/to/my')
...and p.parents[1]will be the next directory up:
...p.parents[1]并将是下一个目录：
>>> p.parents[1]
PosixPath('/path/to')
Etc.
等等。
p.parentis another way to ask for p.parents[0]. You can convert a Pathinto a string and get pretty much what you would expect:
p.parent是另一种请求方式p.parents[0]。您可以将 aPath转换为字符串并获得几乎您所期望的结果：
>>> str(p.parent)
'/path/to/my'
And also on any Pathyou can use the .absolute()method to get an absolute path:
并且在任何Path您都可以使用该.absolute()方法获取绝对路径的情况下：
>>> os.chdir('/etc')
>>> p = pathlib.Path('../relative/path')
>>> str(p.parent)
'../relative'
>>> str(p.parent.absolute())
'/etc/../relative'
Note that os.path.dirnameand pathlibtreat paths with a trailing slash differently. The pathlibparent of some/path/is some:
请注意，os.path.dirname并pathlib以不同的方式对待带有斜杠的路径。的pathlib父级some/path/是some：
>>> p = pathlib.Path('some/path/')
>>> p.parent
PosixPath('some')
While os.path.dirnameon some/path/returns some/path:
虽然os.path.dirname在some/path/收益some/path：
>>> os.path.dirname('some/path/')
'some/path'
