Python 如何在 Django 模型中存储字符串数组？
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How can I store an array of strings in a Django model?
提问by Andrew
I am building a Django data model and I want to be able to store an array of strings in one of the variables; how can I do that?
我正在构建一个 Django 数据模型，我希望能够在其中一个变量中存储一个字符串数组；我怎样才能做到这一点？
e.g.
例如
class myClass(models.Model):
title = models.CharField(max_length=50)
stringArr = models.???
Thanks for the help.
谢谢您的帮助。
采纳答案by Ignacio Vazquez-Abrams
Make another model that holds a string with an optional order, give it a ForeignKeyback to myClass, and store your array in there.
制作另一个模型，其中包含一个带有可选顺序的字符串，将其ForeignKey返回到myClass，并将您的数组存储在那里。
回答by zoldar
You can use some serialization mechanism like JSON. There's a snippet with field definition that could be of some use to you:
您可以使用一些序列化机制，如 JSON。有一个带有字段定义的片段，可能对您有用：
http://djangosnippets.org/snippets/1478/(take a look at the code in the last comment)
http://djangosnippets.org/snippets/1478/（看看最后评论中的代码）
With such field you can seamlessly put strings into a list and assign them to such field. The field abstraction will do the rest. The same with reading.
有了这样的字段，您可以无缝地将字符串放入列表并将它们分配给这样的字段。字段抽象将完成剩下的工作。读书也是一样。
回答by FallenAngel
You can use cPickle...
您可以使用 cPickle ...
class myClass(models.Model):
title = models.CharField(max_length=50)
stringArr = models.TextField()
from cPickle import loads, dumps
data = [ { 'a':'A', 'b':2, 'c':3.0 } ]
obj = Myclass.objects.get(pk=???)
# pickle data into a string-like format
obj.stringArr = dumps(data)
obj.save()
# restore original data
data = loads(obj.stringArr)
回答by Kaustubh Pandey
If you are using PostgreSQL or MongoDB(with djongo) you can do this
如果您使用的是 PostgreSQL 或 MongoDB（使用 djongo），您可以这样做
For PostgreSQL:
对于 PostgreSQL：
from django.contrib.postgres.fields import ArrayField
For MongoDB(with Djongo):
对于 MongoDB（使用 Djongo）：
from djongo import models
from django.contrib.postgres.fields import ArrayField
Then
然后
stringArr = ArrayField(models.CharField(max_length=10, blank=True),size=8)
The above works in both cases.
以上在这两种情况下都有效。
回答by funnydman
You can use JSONFieldfor such functionality:
您可以使用JSONField此类功能：
from django.db import models
from django.contrib.postgres.fields import JSONField
class TestModel(models.Model):
title = models.CharField(max_length=100)
strings = JSONField(default=list, blank=True, null=True)
def __str__(self):
return self.title
for example:
例如：
In [1]: fruits = ['banana', 'apple', 'orange']
In [2]: TestModel.objects.create(title='my set', strings=fruits)
Out[2]: <TestModel: my set>
In [3]: o = TestModel.objects.first()
In [4]: o.strings
Out[4]: ['banana', 'apple', 'orange']
回答by el-Joft
I did this for my model and it worked
我为我的模型做了这个并且它起作用了
from django.contrib.postgres.fields import ArrayField
from django.db import models
class Skill(models.Model):
name = models.CharField(max_length=50)
skills = ArrayField(models.CharField(max_length=200), blank=True)
To create
创造
Skill.objects.create(name='First name', skills=['thoughts', 'django'])
To Query
查询
Skill.objects.filter(skills__contains=['thoughts'])
You can refer to the django documentation for more help
更多帮助可以参考django文档
https://docs.djangoproject.com/en/3.0/ref/contrib/postgres/fields/
https://docs.djangoproject.com/en/3.0/ref/contrib/postgres/fields/
I hope this helps
我希望这有帮助
