java 正则表达式匹配带有特殊字符的单词
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Regex Match Word with special character
提问by Med BEN
I would like to look for any word in a file containing different informations like date and percentage and some strings.
我想在包含不同信息（如日期和百分比以及一些字符串）的文件中查找任何单词。
Input:
输入：
21-02-2015 wordA 22 wordB wordC
Result:
结果：
wordA wordB wordC
Please help me for I am new to regex.
请帮助我，因为我是正则表达式的新手。
回答by Med BEN
This is the regex that could retrieve any string including special character answer found it :
这是可以检索任何字符串的正则表达式，包括找到它的特殊字符答案：
(([a-zA-Z]+)(\W)?([a-zA-Z]+))
([a-zA-Z]+)Look for character in Aa-zZ(\W)look for the special character([a-zA-Z]+)if the special character is in the middle you look for the rest of the word
([a-zA-Z]+)在Aa-zZ 中查找字符(\W)寻找特殊字符([a-zA-Z]+)如果特殊字符在中间，则查找单词的其余部分
回答by Biffen
Java's regex implementation supports character class intersection, for which this is a textbook usecase.
Java 的正则表达式实现支持字符类交集，这是一个教科书用例。
[\w&&[^\d]]will thus match a word character but not a digit. Together with Pattern.UNICODE_CHARACTER_CLASSit should match ‘special characters'.
[\w&&[^\d]]因此将匹配一个单词字符而不是一个数字。连同Pattern.UNICODE_CHARACTER_CLASS它应该匹配“特殊字符”。
Thus this code:
因此这段代码：
import java.util.regex.Matcher;
import java.util.regex.Pattern;
class test {
public static void main(String... args) {
String input = "21-02-2015 wordA 22 wordB wordC F?rtids";
Matcher matcher = Pattern.compile("[\w&&[^\d]]+",
Pattern.UNICODE_CHARACTER_CLASS)
.matcher(input);
while (matcher.find() ) {
System.out.println(matcher.group() );
}
}
}
Produces:
产生：
wordA
wordB
wordC
F?rtids
