Python 仅将字符串拆分为两部分
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Split string into two parts only
提问by Abhishek Velankar
I have a string
我有一个字符串
s = 'abcd qwrre qwedsasd zxcwsacds'
I want to split any string in only two parts at the first occurrence of a whitespace. i.e. a='abcd'and b='qwrre qwedsasd zxcwsacds'
我想在第一次出现空格时将任何字符串分成两部分。即。a='abcd'和b='qwrre qwedsasd zxcwsacds'
If I use a, b=split(' ')it gives me an error because there are too many values to unpack.
如果我使用a, b=split(' ')它会给我一个错误，因为有太多的值需要解包。
回答by TMK
You could use a,b = split(' ', 1).
你可以使用a,b = split(' ', 1).
The second argument 1is the maximum number of splits that would be done.
第二个参数1是将完成的最大拆分数。
s = 'abcd efgh hijk'
a,b = s.split(' ', 1)
print(a) #abcd
print(b) #efgh hijk
For more information on the string split function, see str.splitin the manual.
有关字符串拆分功能的更多信息，请参阅str.split手册中的。
回答by ajxs
From the Python docs
str.split(sep=None, maxsplit=-1)
Return a list of the words in the string, using sep as the delimiter string. If maxsplit is given, at most maxsplit splits are done (thus, the list will have at most maxsplit+1 elements). If maxsplit is not specified or -1, then there is no limit on the number of splits (all possible splits are made).
str.split(sep=None, maxsplit=-1)
返回字符串中单词的列表，使用 sep 作为分隔符字符串。如果给出了 maxsplit，则最多完成 maxsplit 次分割（因此，列表最多有 maxsplit+1 个元素）。如果未指定 maxsplit 或 -1，则对拆分的数量没有限制（进行所有可能的拆分）。
'1 2 3'.split(maxsplit=1)
# ['1', '2 3']
回答by constt
You can use a standard string method partitionwhich searches for a given separator and returns a 3-tuple consisting of string part before it, the separator itself, and the part after it.
您可以使用标准字符串方法partition来搜索给定的分隔符并返回一个 3 元组，它由前面的字符串部分、分隔符本身和后面的部分组成。
>>> s = 'abcd qwrre qwedsasd zxcwsacds'
>>> s.partition(' ')
('abcd', ' ', 'qwrre qwedsasd zxcwsacds')
回答by Zack Atama
You're missing one more parameter in your split, the number of occurrences, try this;
你在你的分割中又缺少一个参数，出现的次数，试试这个；
s='abcd qwrre qwedsasd zxcwsacds'
>>> a, b = s.split(' ', 1)
>>> print(a, b)
回答by JJ123
You can solve this problem by using python "star expression".
您可以通过使用python“星形表达式”来解决这个问题。
s='abcd qwrre qwedsasd zxcwsacds'
a = s.split()
first, *second = a
second = " ".join(second)
"first" takes the first element of the list and " *second" takes the remaining elements.
“first”取列表的第一个元素，“*second”取其余元素。
>>> first
'abcd'
>>> second
'qwrre', 'qwedsasd', 'zxcwsacds'
回答by U10-Forward
Try this:
尝试这个：
s = 'abcd qwrre qwedsasd zxcwsacds'
s1 = s.split()[0]
s2 = ' '.join(s.split()[1:])
print(s1)
print(s2)
Output:
输出：
abcd
qwrre qwedsasd zxcwsacds
Or:
或者：
new_s = ''.join([' s ' if i.isspace() else i for i in s])
a,b = new_s.replace(' s','',1).split(' s ')
print(a)
print(b)
Output:
输出：
abcd
qwrre qwedsasd zxcwsacds
Or even better split also for tabs and newlines:
或者甚至更好地拆分制表符和换行符：
a,b = s.split(None,1)
print(a)
print(b)
Output:
输出：
abcd
qwrre qwedsasd zxcwsacds
回答by Rajat Jain
1.You can split the string like this.
1.你可以像这样拆分字符串。
a = temp.substring(0, s.indexOf(' '));
b = temp.substring(s.indexOf(' ') + 1);
2.or you can do:
2.或者你可以这样做：
a = s[0: s.find(' ')]
b = s[s.find(' ') + 1: ]
3.
3.
a,b = s.split(' ', 1)
print(a)
print(b)
回答by mroman
So, there's a second parameter you can pass as many have pointed out:
因此，正如许多人指出的那样，您可以传递第二个参数：
>>> a, b = "foo bar".split(' ', 1)
but nobody's pointing this out:
但没有人指出这一点：
>>> a, b = "foobar".split(' ', 1)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: need more than 1 value to unpack
You don't want to be using this because it's unsafe unless you're guaranteed to have a string that has only the one space in it. It's better to split it and then check for how many splits you've got and then unpack them:
你不想使用它，因为它是不安全的，除非你保证有一个只有一个空格的字符串。最好将它拆分，然后检查您有多少个拆分，然后解压缩它们：
>>> parts = "foo bar".split(' ', 1)
>>> if len(parts) == 2:
>>> a, b = parts
回答by Michael Swartz
#!python2
s='abcd qwrre qwedsasd zxcwsacds'
s1 = s[0: s.find(' ')]
s2 = s[s.find(' ') + 1: ]
print s1
print s2
'''
abcd
qwrre qwedsasd zxcwsacds
'''
