Python Django Admin：仅对一个模型字段使用自定义小部件
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Django Admin: Using a custom widget for only one model field
提问by Belmin Fernandez
I have a DateTimeFieldfield in my model. I wanted to display it as a checkbox widget in the Django admin site. To do this, I created a custom form widget. However, I do not know how to use my custom widget for onlythis one field.
我的模型中有一个DateTimeField字段。我想将它显示为 Django 管理站点中的复选框小部件。为此，我创建了一个自定义表单小部件。但是，我不知道如何仅将我的自定义小部件用于这一领域。
The Django documentationexplains how to use a custom widget for allfields of a certain type:
在Django文档解释了如何使用自定义窗口小部件的所有特定类型的字段：
class StopAdmin(admin.ModelAdmin):
formfield_overrides = {
models.DateTimeField: {'widget': ApproveStopWidget }
}
This is not granular enough though. I want to change it for only onefield.
但这还不够细化。我只想为一个字段更改它。
采纳答案by Chris Pratt
Create a custom ModelForm for your ModelAdmin and add 'widgets' to its Meta class, like so:
为您的 ModelAdmin 创建一个自定义 ModelForm 并将“小部件”添加到其 Meta 类，如下所示：
class StopAdminForm(forms.ModelForm):
class Meta:
model = Stop
widgets = {
'approve_ts': ApproveStopWidget(),
}
fields = '__all__'
class StopAdmin(admin.ModelAdmin):
form = StopAdminForm
Done!
完毕！
Documentation for this is sort of non-intuitively placed in the ModelForm docs, without any mention to it given in the admin docs. See: Creating forms from models
这方面的文档有点不直观地放在 ModelForm 文档中，在管理文档中没有提及它。请参阅：从模型创建表单
回答by Belmin Fernandez
After digging into the admin, model fieldand form fieldcode, I believe the only way to carry out what I want is by creating a custom model field:
在深入研究admin、模型字段和表单字段代码后，我相信实现我想要的唯一方法是创建自定义模型字段：
models.py
models.py
from django.db import models
from widgets import ApproveStopWidget
class ApproveStopModelField(models.DateTimeField):
pass
class Stop(models.model):
# Other fields
approve_ts = ApproveStopModelField('Approve place', null=True, blank=True)
admin.py
admin.py
from widgets import ApproveStopWidget
from models import ApproveStopModelField
class StopAdmin(admin.ModelAdmin):
formfield_overrides = {
ApproveStopModelField: {'widget': ApproveStopWidget }
}
It gets the job done.
它完成了工作。
For the time being, I'll leave the question unanswered because I have the habit of missing the obvious. Perhaps some Django smartypants has a better solution.
暂时，我不会回答这个问题，因为我有遗漏显而易见的习惯。也许一些 Django smartypants 有更好的解决方案。
回答by Arya-2790306
Django's ModelAdmin.get_changelist_form(self, request, **kwargs) will do the trick for the case of list_editable
Django 的 ModelAdmin.get_changelist_form(self, request, **kwargs) 将解决 list_editable 的问题
class StopAdminForm(forms.ModelForm):
class Meta:
model = Stop
widgets = {
'approve_ts': ApproveStopWidget(),
}
class StopAdmin(admin.ModelAdmin):
form = StopAdminForm
#just return the ModelForm class StopAdminForm
def get_changelist_form(self, request, **kwargs):
return StopAdminForm
Refer to Django Official documentation on this topic
I hope this will help
我希望这个能帮上忙
回答by Andy Baker
Override formfield_for_dbfield like thus:
像这样覆盖 formfield_for_dbfield：
class VehicleAdmin(admin.ModelAdmin):
search_fields = ["name", "colour"]
def formfield_for_dbfield(self, db_field, **kwargs):
if db_field.name == 'colour':
kwargs['widget'] = ColourChooserWidget
return super(VehicleAdmin, self).formfield_for_dbfield(db_field,**kwargs)
(credit to http://www.kryogenix.org/days/2008/03/28/overriding-a-single-field-in-the-django-admin-using-newforms-admin/)
