javascript jQuery。选择所有以 classname 开头的元素
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jQuery. Select all the elements that classname starts with
提问by iLemming
If I have elements with classnames like this:
如果我有这样的类名的元素：
.ses_0 .ses_1 .ses_2 .ses_3
How can I select all the elements and prepend those with some snippet? Something like this:
如何选择所有元素并在这些元素之前添加一些片段？像这样的东西：
var sessions = $('*[class*=ses_]');
for (var i = 0; i < sessions.length; i++)
{
sessions [i].prepend("<img src='/Content/img/caticon"+i+".png' />");
}
That doesn't work of course.
那当然行不通。
Edit:Ahhhh... damn It seems that I need to get not only those classes that start with .ses_ but also <a>elements within. How can I do that?
编辑：啊哈...该死的 看来我不仅需要获取以 .ses_ 开头的那些类，还需要获取其中的 <a>元素。我怎样才能做到这一点？
Basically something that works $(".ses_0 a"), only I need to get all the classes start with ses_
基本上是$(".ses_0 a")可行的，只有我需要让所有的类都以 ses_ 开头
回答by typeof
You're almost there:
你快到了：
// selects all that start with "ses_"
var sessions = $('[class^="ses_"]');
Even though your loop should work, you could also use the
即使你的循环应该工作，你也可以使用
sessions.each(function(index){
this.prepend(... // and so on
});
回答by Oscar
You can use the attribute starts with selector in jQuery: http://api.jquery.com/attribute-starts-with-selector/
您可以在 jQuery 中使用以选择器开头的属性：http: //api.jquery.com/attribute-starts-with-selector/
Beware that it's not nearly as fast as using the regular way of selecting elements.
请注意，它不如使用常规选择元素的方式快。
