C++ 将 boost::uuid 转换为 char*
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Convert boost::uuid to char*
提问by SchwartzE
I am looking to convert a boost::uuid to a const char*. What is the correct syntax for the conversion?
我希望将 boost::uuid 转换为 const char*。转换的正确语法是什么？
回答by SkorKNURE
Just in case, there is also boost::uuids::to_string, that works as follows:
以防万一，还有boost::uuids::to_string，其工作原理如下：
#include <boost/uuid/uuid.hpp>
#include <boost/uuid/uuid_io.hpp>
boost::uuids::uuid a = ...;
const std::string tmp = boost::uuids::to_string(a);
const char* value = tmp.c_str();
回答by user192610
You can do this a bit easier using boost::lexical_cast that uses a std::stringstream under the hood.
你可以使用 boost::lexical_cast 更容易地做到这一点，它在引擎盖下使用 std::stringstream 。
#include <boost/lexical_cast.hpp>
#include <boost/uuid/uuid_io.hpp>
const std::string tmp = boost::lexical_cast<std::string>(theUuid);
const char * value = tmp.c_str();
回答by Reed Copsey
You can include <boost/uuid/uuid_io.hpp>and then use the operators to convert a uuid into a std::stringstream. From there, it's a standard conversion to a const char*as needed.
您可以包含<boost/uuid/uuid_io.hpp>然后使用运算符将 uuid 转换为std::stringstream. 从那里，它是const char*根据需要标准转换为 a 的。
For details, see the Input and Output second of the Uuid documentation.
有关详细信息，请参阅Uuid 文档的输入和输出第二部分。
std::stringstream ss;
ss << theUuid;
const std::string tmp = ss.str();
const char * value = tmp.c_str();
(For details on why you need the "tmp" string, see here.)
（有关为什么需要“tmp”字符串的详细信息，请参见此处。）
回答by Joe
You use the stream functions in boost/uuid/uuid_io.hpp.
您可以使用 boost/uuid/uuid_io.hpp 中的流函数。
boost::uuids::uuid u;
std::stringstream ss;
ss << u;
ss >> u;
回答by Matheus Toniolli
boost::uuids::uuid u;
const char* UUID = boost::uuids::to_string(u).c_str();
It is possible to do a simple and quick conversion.
可以进行简单快速的转换。
