javascript 从谷歌地图解析 json 反向地理编码？
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Parse json from google maps reverse geocode?
提问by Rudiger Kidd
How can I parse through the response from a reverse geocode using Google Maps JavaScript API v3.
如何使用 Google Maps JavaScript API v3 解析来自反向地理编码的响应。
geocoder.geocode({'latLng': latlng}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
if (results[0]) {
infowindow.setContent(results[0].formatted_address);
infowindow.open(map, marker);
}
}
This displays the formatted address fine in the popup, but I'm trying to take other bits out of the response, ideally the street name or route (if no street name found). But when using obj = JSON.parse(json);I keep getting this error in the console.
这会在弹出窗口中很好地显示格式化的地址，但我试图从响应中删除其他位，理想情况下是街道名称或路线（如果没有找到街道名称）。但是在使用时， obj = JSON.parse(json);我不断在控制台中收到此错误。
SyntaxError: JSON.parse: unexpected character
语法错误：JSON.parse：意外字符
if it were PHP I would do a bunch of for eachloops. Is it possible to do something similar in JavaScript ?
如果是 PHP 我会做一堆for each循环。是否可以在 JavaScript 中做类似的事情？
heres a sample
这是一个样本
{
"results" : [
{
"address_components" : [
{
"long_name" : "131",
"short_name" : "131",
"types" : [ "street_number" ]
},
{
"long_name" : "Stubbington Avenue",
"short_name" : "Stubbington Ave",
"types" : [ "route" ]
},
{
"long_name" : "Portsmouth",
"short_name" : "Portsmouth",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Portsmouth",
"short_name" : "Portsmouth",
"types" : [ "administrative_area_level_3", "political" ]
},
{
"long_name" : "Portsmouth",
"short_name" : "Portsmouth",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "England",
"short_name" : "England",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United Kingdom",
"short_name" : "GB",
"types" : [ "country", "political" ]
},
{
"long_name" : "PO2",
"short_name" : "PO2",
"types" : [ "postal_code_prefix", "postal_code" ]
},
{
"long_name" : "Portsmouth",
"short_name" : "Portsmouth",
"types" : [ "postal_town" ]
}
],
"formatted_address" : "131 Stubbington Avenue, Portsmouth PO2, UK",
"geometry" : {
"location" : {
"lat" : 50.8170795,
"lng" : -1.0709701
},
"location_type" : "ROOFTOP",
"viewport" : {
"northeast" : {
"lat" : 50.81842848029149,
"lng" : -1.069621119708498
},
"southwest" : {
"lat" : 50.8157305197085,
"lng" : -1.072319080291502
}
}
},
"types" : [ "street_address" ]
}
],
"status" : "OK"
}
also heres a link to my dev pagewith my current code in full
In summary, how do I get "Stubbington Avenue" from that mess up there ?
总之，我如何从那里的混乱中获得“Stubbington Avenue”？
回答by nebulae
you don't need to JSON.parse those results, it's already json.
你不需要 JSON.parse 这些结果，它已经是 json。
to get "stubbington avenue" out of that valid json, you would use results[0].address_components[1].short_name
要从有效的 json 中获取“stubbington avenue”，您可以使用 results[0].address_components[1].short_name
if you wanted to build the actual address out of those address components, you can loop through and see the values printed out to the console like this:
如果您想从这些地址组件中构建实际地址，您可以循环遍历并查看打印到控制台的值，如下所示：
for(var i in results[0].address_components){
console.log(results[0].address_components[i].short_name);
}
instead of logging them out, append them to a string, or append them to an element, whatever you wish to do with them.
与其将它们注销，不如将它们附加到一个字符串，或将它们附加到一个元素，无论您想对它们做什么。
回答by Manu
I am using Meteor and for Meteor.js it worked a bit differently in my case
我正在使用 Meteor 和 Meteor.js 在我的情况下它的工作方式有点不同
Below is the Meteor Client Side and Server Side Code that worked for me:
以下是对我有用的 Meteor 客户端和服务器端代码：
// Client Side
var zipcode = $('[name=zipcode]').val();
Meteor.call('getLocationbyZipGoogleAPI', zipcode, function(error, result){
if(error){
console.log('error',error.reason);
} else {
var apidata = JSON.parse(result.content);
var longname = apidata.results[0].address_components[3].long_name;
var longaddress = apidata.results[0].formatted_address;
var finaladdress = longaddress+', '+longname;
}
});
// Server Method to Call API
'getLocationbyZipGoogleAPI': function(zip_code){
// do checks
var apiurl = 'http://maps.googleapis.com/maps/api/geocode/json?address='+zip_code+'&sensor=true';
var result = HTTP.get( apiurl );
return result;
}
